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  • 网络流模板(模板题:POJ1273)

    模板题:POJ1273
    EK:

    #include <queue>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    int n,m,jy,map[305][305],c[305][305],a[305],p[305];
    bool vis[305];
    int M(int e)
    {
        int f=0;
        queue<int>q;
        while(1){
            memset(a,0,sizeof(a));
            memset(vis,0,sizeof(vis));
            a[1]=0x3fffffff;vis[1]=1;q.push(1);
            while(!q.empty()){
                jy=q.front();q.pop();
                for(int i=1;i<=e;i++){
                    if(!vis[i]&&map[jy][i]-c[jy][i]>0)
                    {
                        vis[i]=1;
                        a[i]=min(a[jy],map[jy][i]-c[jy][i]);
                        p[i]=jy;
                        q.push(i);
                    }
                }
            }
            if(a[e]==0)break;
            for(int i=e;i!=1;i=p[i]){
                c[i][p[i]]-=a[e];
                c[p[i]][i]+=a[e];
            }
            f+=a[e];
        }
        return f;
    }
    int main()
    {
        while(scanf("%d%d",&n,&m)!=EOF)
        {
            memset(map,0,sizeof(map));
            memset(c,0,sizeof(c));
            memset(p,0,sizeof(p));
            for(int i=1;i<=n;i++)
            {
                register int xx,yy,ee;
                scanf("%d%d%d",&xx,&yy,&ee);
                map[xx][yy]+=ee;
            }
            printf("%d
    ",M(m));
        } 
    }

    Dinic:

    #include <queue>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    #define N 444
    int tot,next[N],first[N],w[N],v[N],n,m,ch[N];
    void add(int from,int to,int weight){
        v[tot]=to;w[tot]=weight;
        next[tot]=first[from];
        first[from]=tot++;
    }
    bool tell(){
        memset(ch,-1,sizeof(ch));
        queue<int> q;
        q.push(1);ch[1]=0;
        while(!q.empty()){
            int t=q.front();q.pop();
            for(int i=first[t];~i;i=next[i])
                if(w[i]&&ch[v[i]]==-1)
                    q.push(v[i]),ch[v[i]]=ch[t]+1;
        }
        return ch[n]!=-1;
    }
    int zeng(int a,int b){
        if(a==n)return b;
        int r=0;
        for(int i=first[a];~i&&b>=r;i=next[i])
            if(ch[a]+1==ch[v[i]]&&w[i]){
                int t=zeng(v[i],min(b-r,w[i]));
                w[i]-=t;w[i^1]+=t;r+=t;
            }
        if(!r)ch[a]=-1;
        return r;
    }
    int dinic(){
        int ans=0,jy;
        while(tell())while(jy=zeng(1,0x3fffffff))ans+=jy;
        return ans;
    }
    int main()
    {
        while(scanf("%d%d",&m,&n)!=EOF){
            memset(first,-1,sizeof(first));
            register int xx,yy,zz;
            tot=0;
            for(int i=1;i<=m;i++){
                scanf("%d%d%d",&xx,&yy,&zz);
                add(xx,yy,zz);add(yy,xx,0);
            }
            printf("%d
    ",dinic());
        }
    }
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  • 原文地址:https://www.cnblogs.com/SiriusRen/p/6532476.html
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