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  • BZOJ 2002 LCT板子题

    思路:

    LCT啊...

    (分块也行)

    不过YOUSIKI出了一道“弹飞大爷” 就不能用分块水过去了

    //By SiriusRen
    #include <cstdio>
    #include <algorithm>
    using namespace std;
    const int N=200050;
    int fa[N],ch[N][2],rev[N],size[N],n,op,q[N],top,a[N],m,xx,yy;
    bool isroot(int x){return ch[fa[x]][0]!=x&&ch[fa[x]][1]!=x;}
    void push_up(int x){size[x]=size[ch[x][0]]+size[ch[x][1]]+1;}
    void push_down(int x){if(rev[x])rev[x]=0,rev[ch[x][0]]^=1,rev[ch[x][1]]^=1,swap(ch[x][0],ch[x][1]);}
    void rotate(int p){
        int q=fa[p],y=fa[q],f=(ch[q][1]==p);
        ch[q][f]=ch[p][!f],fa[ch[q][f]]=q;
        ch[p][!f]=q,fa[p]=y;
        if(!isroot(q)){
            if(ch[y][0]==q)ch[y][0]=p;
            if(ch[y][1]==q)ch[y][1]=p;
        }fa[q]=p;push_up(q);
    }
    void splay(int x){
        q[++top]=x;
        for(int i=x;!isroot(i);i=fa[i])q[++top]=fa[i];
        while(top)push_down(q[top--]);
        for(int y=fa[x];!isroot(x);rotate(x),y=fa[x])if(!isroot(y)){
            if((ch[y][0]==x)^(ch[fa[y]][0]==y))rotate(x);
            else rotate(y);
        }push_up(x);
    }
    void access(int x){for(int t=0;x;t=x,x=fa[x])splay(x),ch[x][1]=t,push_up(x);}
    void makeroot(int x){access(x),splay(x),rev[x]^=1;}
    void link(int x,int y){makeroot(x),fa[x]=y;}
    void cut(int x,int y){makeroot(x),access(y),splay(y);ch[y][0]=fa[x]=0;}
    void split(int x,int y){makeroot(x),access(y),splay(y);}
    int main(){
        scanf("%d",&n);
        for(int i=1;i<=n;i++)scanf("%d",&a[i]);
        for(int i=1;i<=n;i++)link(i,a[i]+i>n?n+1:a[i]+i);
        scanf("%d",&m);
        while(m--){
            scanf("%d%d",&op,&xx),xx++;
            if(op==1)split(n+1,xx),printf("%d
    ",size[xx]-1);
            else scanf("%d",&yy),cut(xx,xx+a[xx]>n?n+1:xx+a[xx]),a[xx]=yy,link(xx,xx+a[xx]>n?n+1:xx+a[xx]);
        }
    }
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  • 原文地址:https://www.cnblogs.com/SiriusRen/p/6532756.html
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