在 .NET 中,可以使用 YamlDotNet 类库解析和生成 YAML 文件。
YamlDotNet : https://github.com/aaubry/YamlDotNet
NuGet 下载:https://www.nuget.org/packages/YamlDotNet/
帮助文档:https://github.com/aaubry/YamlDotNet/wiki
序列化一个对象为 YAML 格式
using YamlDotNet.Serialization;
using YamlDotNet.Serialization.NamingConventions;
...
var person = new Person
{
Name = "Abe Lincoln",
Age = 25,
HeightInInches = 6f + 4f / 12f,
Addresses = new Dictionary<string, Address>{
{ "home", new Address() {
Street = "2720 Sundown Lane",
City = "Kentucketsville",
State = "Calousiyorkida",
Zip = "99978",
}},
{ "work", new Address() {
Street = "1600 Pennsylvania Avenue NW",
City = "Washington",
State = "District of Columbia",
Zip = "20500",
}},
}
};
var serializer = new SerializerBuilder()
.WithNamingConvention(CamelCaseNamingConvention.Instance)
.Build();
var yaml = serializer.Serialize(person);
System.Console.WriteLine(yaml);
// Output:
// name: Abe Lincoln
// age: 25
// heightInInches: 6.3333334922790527
// addresses:
// home:
// street: 2720 Sundown Lane
// city: Kentucketsville
// state: Calousiyorkida
// zip: 99978
// work:
// street: 1600 Pennsylvania Avenue NW
// city: Washington
// state: District of Columbia
// zip: 20500
反序列化 YAML 到对象
using YamlDotNet.Serialization;
using YamlDotNet.Serialization.NamingConventions;
...
var yml = @"
name: George Washington
age: 89
height_in_inches: 5.75
addresses:
home:
street: 400 Mockingbird Lane
city: Louaryland
state: Hawidaho
zip: 99970
";
var deserializer = new DeserializerBuilder()
.WithNamingConvention(UnderscoredNamingConvention.Instance) // see height_in_inches in sample yml
.Build();
//yml contains a string containing your YAML
var p = deserializer.Deserialize<Person>(yml);
var h = p.Addresses["home"];
System.Console.WriteLine($"{p.Name} is {p.Age} years old and lives at {h.Street} in {h.City}, {h.State}.");
// Output:
// George Washington is 89 years old and lives at 400 Mockingbird Lane in Louaryland, Hawidaho.
转换 YAML 为 JSON 格式
var r = new StringReader(@"
scalar: a scalar
sequence:
- one
- two
");
var deserializer = new DeserializerBuilder().Build();
var yamlObject = deserializer.Deserialize(r);
var serializer = new SerializerBuilder()
.JsonCompatible()
.Build();
var json = serializer.Serialize(yamlObject);
Console.WriteLine(json);
该代码会产生以下输出:
{"scalar": "a scalar", "sequence": ["one", "two"]}