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  • 洛谷.4897.[模板]最小割树(Dinic)

    题目链接

    最小割树模板。具体见:https://www.cnblogs.com/SovietPower/p/9734013.html。

    ISAP不知为啥T成0分了。。

    Dinic:

    //1566ms	2.24MB
    #include <cstdio>
    #include <cctype>
    #include <cstring>
    #include <algorithm>
    //#define gc() getchar()
    #define MAXIN 300000
    #define gc() (SS==TT&&(TT=(SS=IN)+fread(IN,1,MAXIN,stdin),SS==TT)?EOF:*SS++)
    typedef long long LL;
    const int N=507,M=3007,INF=1e9;
    
    int n,src,des,A[N],ans[N][N],Enum,H[N],fr[M],to[M],nxt[M],cap[M],Cap[M],pre[N],cur[N],lev[N];
    bool vis[N];
    char IN[MAXIN],*SS=IN,*TT=IN;
    
    inline int read()
    {
    	int now=0;register char c=gc();
    	for(;!isdigit(c);c=gc());
    	for(;isdigit(c);now=now*10+c-'0',c=gc());
    	return now;
    }
    void AE(int w,int v,int u)
    {
    	to[++Enum]=v, fr[Enum]=u, nxt[Enum]=H[u], H[u]=Enum, Cap[Enum]=w;
    	to[++Enum]=u, fr[Enum]=v, nxt[Enum]=H[v], H[v]=Enum, Cap[Enum]=w;
    }
    bool BFS()
    {
    	static int q[N];
    	int n=::n;
    	memset(lev,0,n+2<<2);
    	memcpy(cur,H,n+2<<2);
    	int h=0,t=1; q[0]=src, lev[src]=1;
    	while(h<t)
    	{
    		int x=q[h++];
    		for(int i=H[x]; i; i=nxt[i])
    			if(!lev[to[i]] && cap[i])
    			{
    				lev[to[i]]=lev[x]+1, q[t++]=to[i];
    				if(to[i]==des) return 1;
    			}
    	}
    	return 0;
    }
    int DFS(int x,int flow)
    {
    	if(x==des) return flow;
    	int used=0;
    	for(int &i=cur[x]; i; i=nxt[i])
    		if(cap[i] && lev[to[i]]==lev[x]+1)
    		{
    			int delta=DFS(to[i],std::min(flow-used,cap[i]));
    			if(delta)
    			{
    				cap[i]-=delta, cap[i^1]+=delta, used+=delta;
    				if(used==flow) return flow;
    			}
    		}
    	lev[x]=0;
    	return used;
    }
    int Dinic()
    {
    	int res=0;
    	while(BFS()) res+=DFS(src,INF);
    	return res;
    }
    void Cut(int x)
    {
    	vis[x]=1;
    	for(int i=H[x]; i; i=nxt[i])
    		if(cap[i]&&!vis[to[i]]) Cut(to[i]);
    }
    void Solve(int l,int r)
    {
    	static int tmp[2][N];
    	if(l==r) return;
    
    	for(int i=2; i<=Enum; ++i) cap[i]=Cap[i];
    	src=A[l], des=A[r];
    	int mincut=Dinic();
    
    	memset(vis,0,sizeof vis), Cut(src);
    	for(int i=1; i<=n; ++i)
    		if(vis[i])
    			for(int j=1; j<=n; ++j)
    				if(!vis[j]) ans[j][i]=ans[i][j]=std::min(ans[i][j],mincut);
    
    	int cnt[2]={0,0};
    	for(int i=l,x=A[i]; i<=r; x=A[++i]) tmp[vis[x]][cnt[vis[x]]++]=x;
    	for(int i=0; i<cnt[0]; ++i) A[l+i]=tmp[0][i];
    	for(int i=0,mid=l+cnt[0]; i<cnt[1]; ++i) A[mid+i]=tmp[1][i];
    	Solve(l,l+cnt[0]-1), Solve(l+cnt[0],r);
    }
    
    int main()
    {
    	Enum=1, n=read(); int m=read();
    	for(int i=1; i<=m; ++i) AE(read(),read(),read());
    	for(int i=1; i<=n; ++i) A[i]=i;
    	memset(ans,0x3f,sizeof ans);
    	Solve(1,n);
    	for(int Q=read(); Q--; printf("%d
    ",ans[read()][read()]));
    
    	return 0;
    }
    

    TLE的ISAP:

    #include <cstdio>
    #include <cctype>
    #include <cstring>
    #include <algorithm>
    #define gc() getchar()
    typedef long long LL;
    const int N=507,M=3007,INF=1e9;
    
    int n,src,des,A[N],ans[N][N],Enum,H[N],fr[M],to[M],nxt[M],cap[M],Cap[M],pre[N],lev[N];
    bool vis[N];
    
    inline int read()
    {
    	int now=0;register char c=gc();
    	for(;!isdigit(c);c=gc());
    	for(;isdigit(c);now=now*10+c-'0',c=gc());
    	return now;
    }
    void AE(int w,int v,int u)
    {
    	to[++Enum]=v, fr[Enum]=u, nxt[Enum]=H[u], H[u]=Enum, Cap[Enum]=w;
    	to[++Enum]=u, fr[Enum]=v, nxt[Enum]=H[v], H[v]=Enum, Cap[Enum]=w;
    }
    bool BFS()
    {
    	static int q[N];
    	int n=::n;
    	for(int i=1; i<=n; ++i) lev[i]=n+1;
    	int h=0,t=1; q[0]=des, lev[des]=0;
    	while(h<t)
    	{
    		int x=q[h++];
    		for(int i=H[x]; i; i=nxt[i])
    			if(lev[to[i]]==n+1 && cap[i^1])
    				lev[to[i]]=lev[x]+1, q[t++]=to[i];
    	}
    	return lev[src]<=n;
    }
    inline int Augment()
    {
    	int mn=INF;
    	for(int i=des; i!=src; i=fr[pre[i]])
    		mn=std::min(mn,cap[pre[i]]);
    	for(int i=des; i!=src; i=fr[pre[i]])
    		cap[pre[i]]-=mn, cap[pre[i]^1]+=mn;
    	return mn;
    }
    int ISAP()
    {
    	static int cur[N],num[N];
    	if(!BFS()) return 0;
    	memset(num,0,n+2<<2);
    	for(int i=1; i<=n; ++i) cur[i]=H[i],++num[lev[i]];
    	int res=0,x=src;
    	while(lev[src]<=n)
    	{
    		if(x==des) x=src,res+=Augment();
    		bool can=0;
    		for(int i=cur[x]; i; i=nxt[i])
    			if(lev[to[i]]==lev[x]-1 && cap[i])
    			{
    				can=1, cur[x]=i, pre[x=to[i]]=i;
    				break;
    			}
    		if(!can)
    		{
    			int mn=n;
    			for(int i=H[x]; i; i=nxt[i])
    				if(cap[i]) mn=std::min(mn,lev[to[i]]);
    			if(!--num[lev[x]]) break;
    			++num[lev[x]=mn+1], cur[x]=H[x];
    			if(x!=src) x=fr[pre[x]];
    		}
    	}
    	return res;
    }
    void Cut(int x)
    {
    	vis[x]=1;
    	for(int i=H[x]; i; i=nxt[i])
    		if(cap[i]&&!vis[to[i]]) Cut(to[i]);
    }
    void Solve(int l,int r)
    {
    	static int tmp[2][N];
    	if(l==r) return;
    
    	for(int i=2; i<=Enum; ++i) cap[i]=Cap[i];
    	src=A[l], des=A[r];
    	int mincut=ISAP();
    
    	memset(vis,0,sizeof vis), Cut(src);
    	for(int i=1; i<=n; ++i)
    		if(vis[i])
    			for(int j=1; j<=n; ++j)
    				if(!vis[j]) ans[j][i]=ans[i][j]=std::min(ans[i][j],mincut);
    
    	int cnt[2]={0,0};
    	for(int i=l,x=A[i]; i<=r; x=A[++i]) tmp[vis[x]][cnt[vis[x]]++]=x;
    	for(int i=0; i<cnt[0]; ++i) A[l+i]=tmp[0][i];
    	for(int i=0,mid=l+cnt[0]; i<cnt[1]; ++i) A[mid+i]=tmp[1][i];
    	Solve(l,l+cnt[0]-1), Solve(l+cnt[0],r);
    }
    
    int main()
    {
    	Enum=1, n=read(); int m=read();
    	for(int i=1; i<=m; ++i) AE(read(),read(),read());
    	for(int i=1; i<=n; ++i) A[i]=i;
    	memset(ans,0x3f,sizeof ans);
    	Solve(1,n);
    	for(int Q=read(); Q--; printf("%d
    ",ans[read()][read()]));
    
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/SovietPower/p/9811085.html
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