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  • Validate Binary Search Tree

    Given a binary tree, determine if it is a valid binary search tree (BST).

    Assume a BST is defined as follows:

    • The left subtree of a node contains only nodes with keys less than the node's key.
    • The right subtree of a node contains only nodes with keys greater than the node's key.
    • Both the left and right subtrees must also be binary search trees.

    confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ.

     
    /**
     * Definition for a binary tree node.
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    
    class Solution {
    
    public:
        void _inOrder(TreeNode* root, vector<int> &res) {
    
            if (NULL == root) {
                return;
            }
            
            _inOrder(root->left, res);
            res.push_back(root->val);
            _inOrder(root->right, res);
        }
    
    
        bool isValidBST(TreeNode* root) {
            vector<int> res;
            
            _inOrder(root, res);
            
            int i;
            for (i = 1; i< res.size(); i++) {
                if (res[i] <= res[i - 1]) {
                    return false;
                }
            }
            return true;
        }
    };
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  • 原文地址:https://www.cnblogs.com/SpeakSoftlyLove/p/5185040.html
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