Codeforces Round 56-B. Letters Rearranging（思维）

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

You are given a string ss consisting only of lowercase Latin letters.

You can rearrange all letters of this string as you wish. Your task is to obtain a good string by rearranging the letters of the given string or report that it is impossible to do it.

Let's call a string good if it is not a palindrome. Palindrome is a string which is read from left to right the same as from right to left. For example, strings "abacaba", "aa" and "z" are palindromes and strings "bba", "xd" are not.

You have to answer tt independent queries.

Input

The first line of the input contains one integer tt (1≤t≤1001≤t≤100) — number of queries.

Each of the next tt lines contains one string. The ii-th line contains a string sisi consisting only of lowercase Latin letter. It is guaranteed that the length of sisi is from 11 to 10001000 (inclusive).

Output

Print tt lines. In the ii-th line print the answer to the ii-th query: -1 if it is impossible to obtain a good string by rearranging the letters of sisiand any good string which can be obtained from the given one (by rearranging the letters) otherwise.

Example

input

Copy

3
aa
abacaba
xdd

output

Copy

-1
abaacba
xdd

Note

In the first query we cannot rearrange letters to obtain a good string.

Other examples (not all) of correct answers to the second query: "ababaca", "abcabaa", "baacaba".

In the third query we can do nothing to obtain a good string.

题解：排个序看是否是回文串即可

代码：

#include<cstdio>
#include<iostream>
#include<algorithm>
#include<cstring>

using namespace std;


int main()
{
	int n;
	cin>>n;
	char s1[1005];
	for(int t=0;t<n;t++)
	{
		scanf("%s",s1);
		sort(s1,s1+strlen(s1));
		int cnt=0;
		for(int j=1;j<strlen(s1);j++)
		{
			if(s1[j]==s1[j-1])
			{
				cnt++;
			}
		}
		if(cnt==strlen(s1)-1)
		{
			printf("-1
");
		}
		else
		{
			puts(s1);
		}
	}
	

	return 0;
}