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  • HDU

    I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B. 

    Input

    The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000. 

    Output

    For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases. 

    Sample Input

    2
    1 2
    112233445566778899 998877665544332211

    Sample Output

    Case 1:
    1 + 2 = 3
    
    Case 2:
    112233445566778899 + 998877665544332211 = 1111111111111111110

    题解:模拟加法,加进位之间的关系即可

    代码:

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    
    using namespace std;
    
    int main () {
    	char a[8000],b[8000];
    	int na[8000],nb[8000],sum[8000],pre,flag=1;
    	int t;
    	scanf("%d",&t);
    	while (t--) {
    		memset(sum,0,sizeof(sum));
    		memset(na,0,sizeof(na));
    		memset(nb,0,sizeof(nb));
    		scanf("%s%s",a,b);
    		pre=0;
    		int lena=strlen(a);
    		int lenb=strlen(b);
    		for (int i=0; i<lena; i++)
    			na[lena-1-i]=a[i]-'0';
    		for (int j=0; j<lenb; j++)
    			nb[lenb-1-j]=b[j]-'0';
    		int lenx=lena>lenb?lena:lenb;
    		for (int k=0; k<lenx; k++) {
    			sum[k]=na[k]+nb[k]+pre/10;
    			pre=sum[k];
    		}
    		while (pre>9) {
    			sum[lenx]=pre/10%10;
    			lenx++;
    			pre/=10;
    		}
    		printf ("Case %d:
    ",flag++);
    		printf ("%s + %s = ",a,b);
    		for (int i=lenx-1; i>=0; i--) {
    			printf ("%d",sum[i]%10);
    		}
    		printf ("
    ");
    		if (t)
    			printf ("
    ");
    	}
    
    	return 0;
    }
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  • 原文地址:https://www.cnblogs.com/Staceyacm/p/10782005.html
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