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  • LeetCode --- Add Two Numbers

    题目链接

    说来算是个基础题目,可是还是各种CE,各种WA,基础还是不扎实。

    附上代码:

     1 /**
     2  * Definition for singly-linked list.
     3  * struct ListNode {
     4  *     int val;
     5  *     ListNode *next;
     6  *     ListNode(int x) : val(x), next(NULL) {}
     7  * };
     8  */
     9 class Solution {
    10 public:
    11     ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) {
    12         if (l1 == NULL) return l2;
    13         if (l2 == NULL) return l1;
    14         // q: keep trace of the linked list that has been produced as the answer
    15         // ll1: keep trace of l1
    16         // ll2: keep trace of l2
    17         ListNode *head(NULL), *q(NULL), *ll1 = l1, *ll2 = l2;
    18         // c: holds the carry digit 
    19         int c = 0;
    20         while (ll1!=NULL || ll2!=NULL) {
    21             // sum: holds sum of ll1->val, ll2->val and c
    22             int sum = 0;
    23             if (ll1 != NULL) {
    24                 sum += ll1->val;
    25                 ll1 = ll1->next;
    26             }
    27             if (ll2 != NULL) {
    28                 sum += ll2->val;
    29                 ll2 = ll2->next;
    30             }
    31             sum += c;
    32             ListNode *p = new ListNode(sum%10);
    33             c = sum >= 10 ? 1 : 0;
    34             if (head == NULL) {
    35                 head = q = p;
    36             } else {
    37                 q->next = p;
    38                 q = p;
    39             }
    40         }
    41         if (c) {
    42             q->next = new ListNode(c);
    43         }
    44         return head;
    45     }
    46 };
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  • 原文地址:https://www.cnblogs.com/Stomach-ache/p/3754409.html
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