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  • BZOJ5104 二次剩余板子

    https://www.lydsy.com/JudgeOnline/problem.php?id=5104

     

    https://www.zybuluo.com/mdeditor#1210359

    #include<iostream>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<algorithm>
    #include<map>
    #include<ctime>
    #include<cmath>
    #define re register
    #define rep(i,s,t) for(re int i=s;i<=t;++i)
    using namespace std;
    typedef long long ll;
    const int sq5=383008016,ny2=500000005,mod=1000000009,inf=0x7fffffff;
    int n,w;
    map<int,int>ma;
    struct com{
        int x,y;
        inline com operator*(const com &a){
            return (com){(1ll*x*a.x+1ll*y*a.y%mod*w)%mod,(1ll*x*a.y+1ll*y*a.x)%mod};
        }
    };
    inline int fp(int a,int b){
        int res=1;
        for(;b;b>>=1,a=1ll*a*a%mod)
            if(b&1)
                res=1ll*res*a%mod;
        return res;
    }
    inline int sq(int n){
        if(fp(n,(mod-1)/2)!=1)return 0;
        int a;
        for(a=rand();fp((1ll*a*a%mod-n+mod)%mod,(mod-1)/2)==1;a=rand());
        com x=(com){a,mod-1},ans=(com){1,0};
        int y=(mod+1)/2;w=(1ll*a*a%mod+mod-n)%mod;
        for(;y;y>>=1,x=x*x)
            if(y&1)ans=ans*x;
        return ans.x;
    }
    inline int BSGS(int t,int n){
        int blo=sqrt(mod),ny=fp(t,mod-2),tmp=n;
        ma.clear(),ma[n]=mod;
        rep(i,1,blo-1)tmp=1ll*tmp*ny%mod,ma[tmp]=!ma[tmp]?i:ma[tmp];
        if(ma[1])return ma[1]%mod;
        tmp=1;t=fp(t,blo);
        rep(i,1,blo){
            tmp=1ll*tmp*t%mod;
            if(ma[tmp])
                return(i*blo+ma[tmp])%mod;
        }
        return -1;
    }
    int main(){
        srand(time(0));
        scanf("%d",&n);
        int t=1ll*(sq5+1)*ny2%mod,T=1ll*sq5*n%mod;
        int ans=inf,x,y,r0=sq(5ll*n*n%mod+4),r1=sq(5ll*n*n%mod-4);
        x=1ll*(T+r0)*ny2%mod;y=BSGS(t,x);if(y>-1&&!(y&1)&&r0)ans=min(ans,y);
        x=1ll*(T+mod-r0)*ny2%mod;y=BSGS(t,x);if(y>-1&&!(y&1)&&r0)ans=min(ans,y);
        x=1ll*(T+r1)*ny2%mod;y=BSGS(t,x);if(y>-1&&(y&1)&&r1)ans=min(ans,y);
        x=1ll*(T+mod-r1)*ny2%mod;y=BSGS(t,x);if(y>-1&&(y&1)&&r1)ans=min(ans,y);
        if(ans==inf)puts("-1");
        else printf("%d",ans);
        return 0;
    }
    code
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  • 原文地址:https://www.cnblogs.com/Stump/p/9295879.html
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