unittest 排序

解决方案一直接改unittest源代码：

把排序240行逻辑注释掉，237行获取成员方法按照dict方法替换原有的dir() 方法

 验证效果：

比较猥琐的解决方案2

获取成员变量class.__dict__.keys()

filter过滤符合要求成员，由于3.x成员dict属性是支持有序的

# coding=utf-8
import unittest
from inspect import isfunction

def raw_members(class_name:object):
"""
get all unsort members test_* name list
eg it also work well :
list(filter(lambda x: not x.startswith("__") and not x.endswith("__")
and x.startswith("test_") ,TestHetero.__dict__.keys()))

"""
return list(filter(lambda x: not x.startswith("__") and not x.endswith("__") and x.startswith("test_")
and isfunction(eval(class_name.__name__+".%s"%x)) and callable(eval(class_name.__name__+".%s"%x )),
class_name.__dict__.keys()))

第二步：
制作suite原始顺序添加的suite:

suite=unittest.TestSuite()

suite.addTests([TestHetero("%s"%value) for value in raw_members(TestHetero)])
print(suite)
unittest.TextTestRunner(verbosity=2).run(suite)

结果验证：并没有按照ascii 0-9 A-Z a-z自动排序而是按自己书写顺序执行，改装结束

<unittest.suite.TestSuite tests=[<__main__.TestHetero testMethod=test_Account>, <__main__.TestHetero testMethod=test_user>, <__main__.TestHetero testMethod=test_001>, <__main__.TestHetero testMethod=test_002>]>
test_Account (__main__.TestHetero) ... ok
Account
user
001
test_user (__main__.TestHetero) ... ok
002
test_001 (__main__.TestHetero) ... ok
test_002 (__main__.TestHetero) ... ok

----------------------------------------------------------------------
Ran 4 tests in 0.001s

OK

测试类：

class TestHetero(unittest.TestCase):

    @classmethod
    def setUpClass(cls):
        pass
    @classmethod
    def tearDownClass(self):
        pass

    def  test_Account(self):
        print("Account")

    def test_user(self):
        print("user")
    def test_001(self):
        # unittest.TestLoader.getTestCaseNames()
        print("001")
    def test_002(self):

        print("002")