LightOJ 1370- Bi-shoe and Phi-shoe

https://vjudge.net/contest/312835#problem

Bamboo Pole-vault is a massively popular sport in Xzhiland. And Master Phi-shoe is a very popular coach for his success. He needs some bamboos for his students, so he asked his assistant Bi-Shoe to go to the market and buy them. Plenty of Bamboos of all possible integer lengths (yes!) are available in the market. According to Xzhila tradition,

Score of a bamboo = Φ (bamboo's length)

(Xzhilans are really fond of number theory). For your information, Φ (n) = numbers less than n which are relatively prime (having no common divisor other than 1) to n. So, score of a bamboo of length 9 is 6 as 1, 2, 4, 5, 7, 8 are relatively prime to 9.

The assistant Bi-shoe has to buy one bamboo for each student. As a twist, each pole-vault student of Phi-shoe has a lucky number. Bi-shoe wants to buy bamboos such that each of them gets a bamboo with a score greater than or equal to his/her lucky number. Bi-shoe wants to minimize the total amount of money spent for buying the bamboos. One unit of bamboo costs 1 Xukha. Help him.

Input

Input starts with an integer T (≤ 100), denoting the number of test cases.

Each case starts with a line containing an integer n (1 ≤ n ≤ 10000) denoting the number of students of Phi-shoe. The next line contains n space separated integers denoting the lucky numbers for the students. Each lucky number will lie in the range [1, 10⁶].

Output

For each case, print the case number and the minimum possible money spent for buying the bamboos. See the samples for details.

Sample Input

3

5

1 2 3 4 5

6

10 11 12 13 14 15

2

1 1

Sample Output

Case 1: 22 Xukha

Case 2: 88 Xukha

Case 3: 4 Xukha

Score就是对应长度的欧拉函数

从lucky number+1开始递增 选择第一个出现的质数作为cost

代码

#include <bits/stdc++.h>
#include <iostream>
#include <cstring>
#include <stack>
#include <cstdlib>
#include <queue>
#include <cmath>
#include <cstdio>
#include <algorithm>
#include <string>
#include <vector>
#include <list>
#include <iterator>
#include <set>
#include <map>
#include <utility>
#include <iomanip>
#include <ctime>
#include <sstream>
#include <bitset>
#include <deque>
#include <limits>
#include <numeric>
#include <functional>

#define gc getchar()
#define mem(a) memset(a,0,sizeof(a))
#define mod 1000000007
#define sort(a,n,int) sort(a,a+n,less<int>())
#define fread() freopen("in.in","r",stdin)
#define fwrite() freopen("out.out","w",stdout)
using namespace std;

typedef long long ll;
typedef char ch;
typedef double db;

const int maxn=1e5+10;
int aa[maxn];

int fun(int a)
{
    int i , m;
    for(int n = a+1;;n++)
    {
            m = sqrt(n);
            for(i=2;i<=m;i++)
            {
                if(n%i==0) break;
            }
            if (i>m)
            {
                return n;
            }    
    }
} 

int main()
{
    int t , n , sum = 0;
    int a[10005] = {0};
    cin >> t;
    for(int j = 1;j<=n;j++)
    {
        cin >> n;
        for(int i = 0;i<n;i++)
        {
            cin>>a[i];
        }
        for(int i = 0;i<n;i++)
        {
            sum+=fun(a[i]);
        } 
    cout<<"Case "<<j<<": "<<sum<<" Xukha";
    sum = 0;
    }
    return 0;
}