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  • H. GSS and Simple Math Problem 高精度乘法模板

    链接:https://www.nowcoder.com/acm/contest/104/G
    来源:牛客网

    题目描述

    Given n positive integers , your task is to calculate the product of these integers, The answer is less than
    题解:直接python高精度
    坑:c++高精度会T
    紫书上的高精度乘法改不来
    t = int(input())
    p=1
    for i in range(t):   
        s = int(input())
        p=p*s
    print (p)

    附:紫书上的高精度乘法:

    #include<bits/stdc++.h>
    #define lson (rt<<1)
    #define rson (rt<<1|1)
    #define mp make_pair
    #define fi first
    #define se second
    using namespace std;
    typedef long long ll;
    typedef pair<int,int> pii;
    typedef pair<ll,ll> pll;
    const int MAXN=1111;
    const int MOD=(int)1e9+7;
    struct BigInt{
        const static int Base=(int)1e9;
        const static int Len=9;
        vector<int>a;
        BigInt(){a={0};}
        BigInt(const char *str,const int &l,const int &r){
            for(int i=r-Len+1;;i-=Len){
                int tmp=0;
                if(i<l){
                    for(int j=l;j<i+Len;j++)tmp=tmp*10+str[j]-'0';
                    a.push_back(tmp);
                    break;
                }
                for(int j=i;j<i+Len;j++)tmp=tmp*10+str[j]-'0';
                a.push_back(tmp);
     
            }
            while(a.back()==0&&a.size()>1)a.pop_back();
        }
        BigInt operator *(const BigInt &b)const{
            BigInt res;
            res.a.resize(a.size()+b.a.size());
            for(int i=0;i<(int)a.size();i++){
                int up=0;
                for(int j=0;j<(int)b.a.size();j++){
                    ll tmp=1ll*a[i]*b.a[j]+res.a[i+j]+up;
                    res.a[i+j]=tmp%Base;
                    up=tmp/Base;
                }
                if(up!=0)res.a[i+(int)b.a.size()]=up;
            }
            while(res.a.back()==0&&res.a.size()>1)res.a.pop_back();
            return res;
        }
        void display(){
            printf("%d",a.back());
            for(int i=(int)a.size()-2;i>=0;i--)printf("%09d",a[i]);
     
        }
    }ans;
    char str[100005];
    int main()
    {
        int n;
        scanf("%d",&n);
        for(int i=1;i<=n;i++){
            scanf("%s",str);
            if(i==1)ans=BigInt(str,0,strlen(str)-1);
            else {
                ans=ans*BigInt(str,0,strlen(str)-1);
            }
        }
        ans.display();
        return 0;
    }
    /*
    20 1
    12345678912345678912
    */

    以及某丧心病狂的高精度

    #include <bits/stdc++.h>
    #pragma comment(linker, "/STACK:1024000000,1024000000")
    #define mem(a,b) memset((a),(b),sizeof(a))
    #define MP make_pair
    #define pb push_back
    #define fi first
    #define se second
    #define sz(x) (int)x.size()
    #define all(x) x.begin(),x.end()
    using namespace std;
    #define _GLIBCXX_PERMIT_BACKWARD_HASH
    #include <ext/hash_map>
    using namespace __gnu_cxx;
    struct str_hash{size_t operator()(const string& str)const{return __stl_hash_string(str.c_str());}};
    typedef long long ll;
    typedef unsigned long long ull;
    #define PII pair<int,int>
    #define PLL pair<ll,ll>
    #define PDD pair<double,double>
    const int INF=0x3f3f3f3f;
    const ll LLINF=0x3f3f3f3f3f3f3f3f;
    const double PI=acos(-1.0);
    const double eps=1e-8;
    const int MAX=2e6+10;
    const ll mod=1e9+7;
    const int DIGIT=9;
    const int DEPTH=1000000000;
    const int MAXN=12000;
    typedef ll bignum_t[MAXN+1];
    ll read(bignum_t a,istream&is=cin)
    {
        char buf[MAXN*DIGIT+1],ch;
        ll i,j;
        memset((void*)a,0,sizeof(bignum_t));
        if(!(is>>buf))return 0;
        for(a[0]=strlen(buf),i=a[0]/2-1;i>=0;i--)
        ch=buf[i],buf[i]=buf[a[0]-1-i],buf[a[0]-1-i]=ch;
        for(a[0]=(a[0]+DIGIT-1)/DIGIT,j=strlen(buf);j<a[0]*DIGIT;buf[j++]='0');
        for(i=1;i<=a[0];i++)
        for(a[i]=0,j=0;j<DIGIT;j++)
        a[i]=a[i]*10+buf[i*DIGIT-1-j]-'0';
        for(;!a[a[0]]&&a[0]>1;a[0]--);
        return 1;
    }
    void write(const bignum_t a,ostream&os=cout)
    {
        ll i,j ;
        for(os<<a[i=a[0]],i--;i;i--)
        os<<setw(DIGIT)<<setfill('0')<<a[i];
    }
    ll comp(const bignum_t a,const bignum_t b)
    {
        ll i ;
        if(a[0]!=b[0]) return a[0]-b[0];
        for(i=a[0];i;i--)
        if(a[i]!=b[i])
        return a[i]-b[i];
        return 0 ;
    }
    ll comp(const bignum_t a,const ll b)
    {
        ll c[12]={1};
        for(c[1]=b;c[c[0]]>=DEPTH;c[c[0]+1]=c[c[0]]/DEPTH,c[c[0]]%=DEPTH,c[0]++);
        return comp(a,c);
    }
    ll comp(const bignum_t a,const ll c,const ll d,const bignum_t b)
    {
        ll i,t=0,O=-DEPTH*2;
        if(b[0]-a[0]<d&&c)
        return 1 ;
        for(i=b[0];i>d;i--)
        {
            t=t*DEPTH+a[i-d]*c-b[i];
            if(t>0)return 1;
            if(t<O)return 0;
        }
        for(i=d;i;i--)
        {
            t=t*DEPTH-b[i];
            if(t>0)return 1;
            if(t<O)return 0;
        }
        return t>0 ;
    }
    void add(bignum_t a,const bignum_t b)
    {
        ll i ;
        for(i=1;i<=b[0];i++)
        if((a[i]+=b[i])>=DEPTH)
        a[i]-=DEPTH,a[i+1]++;
        if(b[0]>=a[0])
        a[0]=b[0];
        else
        for(;a[i]>=DEPTH&&i<a[0];a[i]-=DEPTH,i++,a[i]++);
        a[0]+=(a[a[0]+1]>0);
    }
    void add(bignum_t a,const ll b)
    {
        ll i=1;
        for(a[1]+=b;a[i]>=DEPTH&&i<a[0];a[i+1]+=a[i]/DEPTH,a[i]%=DEPTH,i++);
        for(;a[a[0]]>=DEPTH;a[a[0]+1]=a[a[0]]/DEPTH,a[a[0]]%=DEPTH,a[0]++);
    }
    void sub(bignum_t a,const bignum_t b)
    {
        ll i;
        for(i=1;i<=b[0];i++)
        if((a[i]-=b[i])<0)
        a[i+1]--,a[i]+=DEPTH;
        for(;a[i]<0;a[i]+=DEPTH,i++,a[i]--);
        for(;!a[a[0]]&&a[0]>1;a[0]--);
    }
    void sub(bignum_t a,const ll b)
    {
        ll i=1;
        for(a[1]-=b;a[i]<0;a[i+1]+=(a[i]-DEPTH+1)/DEPTH,a[i]-=(a[i]-DEPTH+1)/DEPTH*DEPTH,i++);
        for(;!a[a[0]]&&a[0]>1;a[0]--);
    }
    void sub(bignum_t a,const bignum_t b,const ll c,const ll d)
    {
        ll i,O=b[0]+d;
        for(i=1+d;i<=O;i++)
        if((a[i]-=b[i-d]*c)<0)
        a[i+1]+=(a[i]-DEPTH+1)/DEPTH,a[i]-=(a[i]-DEPTH+1)/DEPTH*DEPTH ;
        for(;a[i]<0;a[i+1]+=(a[i]-DEPTH+1)/DEPTH,a[i]-=(a[i]-DEPTH+1)/DEPTH*DEPTH,i++);
        for(;!a[a[0]]&&a[0]>1;a[0]--);
    }
    void mul(bignum_t c,const bignum_t a,const bignum_t b)
    {
        ll i,j;
        memset((void*)c,0,sizeof(bignum_t));
        for(c[0]=a[0]+b[0]-1,i=1;i<=a[0];i++)
        for(j=1;j<=b[0];j++)
        if((c[i+j-1]+=a[i]*b[j])>=DEPTH)
        c[i+j]+=c[i+j-1]/DEPTH,c[i+j-1]%=DEPTH;
        for(c[0]+=(c[c[0]+1]>0);!c[c[0]]&&c[0]>1;c[0]--);
    }
    void mul(bignum_t a,const ll b)
    {
        ll i;
        for(a[1]*=b,i=2;i<=a[0];i++)
        {
            a[i]*=b ;
            if(a[i-1]>=DEPTH)
            a[i]+=a[i-1]/DEPTH,a[i-1]%=DEPTH;
        }
        for(;a[a[0]]>=DEPTH;a[a[0]+1]=a[a[0]]/DEPTH,a[a[0]]%=DEPTH,a[0]++);
        for(;!a[a[0]]&&a[0]>1;a[0]--);
    }
    void mul(bignum_t b,const bignum_t a,const ll c,const ll d)
    {
        ll i;
        memset((void*)b,0,sizeof(bignum_t));
        for(b[0]=a[0]+d,i=d+1;i<=b[0];i++)
        if((b[i]+=a[i-d]*c)>=DEPTH)
        b[i+1]+=b[i]/DEPTH,b[i]%=DEPTH ;
        for(;b[b[0]+1];b[0]++,b[b[0]+1]=b[b[0]]/DEPTH,b[b[0]]%=DEPTH);
        for(;!b[b[0]]&&b[0]>1;b[0]--);
    }
    void div(bignum_t c,bignum_t a,const bignum_t b)
    {
        ll h,l,m,i;
        memset((void*)c,0,sizeof(bignum_t));
        c[0]=(b[0]<a[0]+1)?(a[0]-b[0]+2):1 ;
        for(i=c[0];i;sub(a,b,c[i]=m,i-1),i--)
        for(h=DEPTH-1,l=0,m=(h+l+1)>>1;h>l;m=(h+l+1)>>1)
        if(comp(b,m,i-1,a))h=m-1;
        else l=m;
        for(;!c[c[0]]&&c[0]>1;c[0]--);
        c[0]=c[0]>1?c[0]:1;
    }
    void div(bignum_t a,const ll b,ll&c)
    {
        ll i;
        for(c=0,i=a[0];i;c=c*DEPTH+a[i],a[i]=c/b,c%=b,i--);
        for(;!a[a[0]]&&a[0]>1;a[0]--);
    }
    void sqrt(bignum_t b,bignum_t a)
    {
        ll h,l,m,i;
        memset((void*)b,0,sizeof(bignum_t));
        for(i=b[0]=(a[0]+1)>>1;i;sub(a,b,m,i-1),b[i]+=m,i--)
        for(h=DEPTH-1,l=0,b[i]=m=(h+l+1)>>1;h>l;b[i]=m=(h+l+1)>>1)
        if(comp(b,m,i-1,a))h=m-1;
        else l=m;
        for(;!b[b[0]]&&b[0]>1;b[0]--);
        for(i=1;i<=b[0];b[i++]>>=1);
    }
    ll length(const bignum_t a)
    {
        ll t,ret;
        for(ret=(a[0]-1)*DIGIT,t=a[a[0]];t;t/=10,ret++);
        return ret>0?ret:1;
    }
    ll digit(const bignum_t a,const ll b)
    {
        ll i,ret;
        for(ret=a[(b-1)/DIGIT+1],i=(b-1)%DIGIT;i;ret/=10,i--);
        return ret%10;
    }
    ll zeronum(const bignum_t a)
    {
        ll ret,t;
        for(ret=0;!a[ret+1];ret++);
        for(t=a[ret+1],ret*=DIGIT;!(t%10);t/=10,ret++);
        return ret;
    }
    void comp(ll*a,const ll l,const ll h,const ll d)
    {
        ll i,j,t;
        for(i=l;i<=h;i++)
        for(t=i,j=2;t>1;j++)
        while(!(t%j))
        a[j]+=d,t/=j;
    }
    void convert(ll*a,const ll h,bignum_t b)
    {
        ll i,j,t=1;
        memset(b,0,sizeof(bignum_t));
        for(b[0]=b[1]=1,i=2;i<=h;i++)
        if(a[i])
        for(j=a[i];j;t*=i,j--)
        if(t*i>DEPTH)
        mul(b,t),t=1;
        mul(b,t);
    }
    #define SGN(x) ((x)>0?1:((x)<0?-1:0))
    #define ABS(x) ((x)>0?(x):-(x))
    ll read(bignum_t a,ll&sgn,istream&is=cin)
    {
        char str[MAXN*DIGIT+2],ch,*buf;
        ll i,j;
        memset((void*)a,0,sizeof(bignum_t));
        if(!(is>>str))return 0;
        buf=str,sgn=1;
        if(*buf=='-')sgn=-1,buf++;
        for(a[0]=strlen(buf),i=a[0]/2-1;i>=0;i--)
        ch=buf[i],buf[i]=buf[a[0]-1-i],buf[a[0]-1-i]=ch ;
        for(a[0]=(a[0]+DIGIT-1)/DIGIT,j=strlen(buf);j<a[0]*DIGIT;buf[j++]='0');
        for(i=1;i<=a[0];i++)
        for(a[i]=0,j=0;j<DIGIT;j++)
        a[i]=a[i]*10+buf[i*DIGIT-1-j]-'0';
        for(;!a[a[0]]&&a[0]>1;a[0]--);
        if(a[0]==1&&!a[1])sgn=0;
        return 1;
    }
    struct bigint
    {
        bignum_t num;
        ll sgn;
        bigint(ll v){*this = v;}
        inline bigint()
        {
            memset(num,0,sizeof(bignum_t));
            num[0]=1;
            sgn=0;
        }
        inline ll operator!()
        {
            return num[0]==1&&!num[1];
        }
        inline bigint&operator=(const bigint&a)
        {
            memcpy(num,a.num,sizeof(bignum_t));
            sgn=a.sgn;
            return*this;
        }
        inline bigint&operator=(const ll a)
        {
            memset(num,0,sizeof(bignum_t));
            num[0]=1;
            sgn=SGN (a);
            add(num,sgn*a);
            return*this;
        }
        inline bigint&operator+=(const bigint&a)
        {
            if(sgn==a.sgn)add(num,a.num);
            else if(sgn&&a.sgn)
            {
                ll ret=comp(num,a.num);
                if(ret>0)sub(num,a.num);
                else if(ret<0)
                {
                    bignum_t t;
                    memcpy(t,num,sizeof(bignum_t));
                    memcpy(num,a.num,sizeof(bignum_t));
                    sub (num,t);
                    sgn=a.sgn;
                }
                else memset(num,0,sizeof(bignum_t)),num[0]=1,sgn=0;
            }
            else if(!sgn) memcpy(num,a.num,sizeof(bignum_t)),sgn=a.sgn;
            return*this;
        }
        inline bigint&operator+=(const ll a)
        {
            if(sgn*a>0)add(num,ABS(a));
            else if(sgn&&a)
            {
                ll  ret=comp(num,ABS(a));
                if(ret>0)sub(num,ABS(a));
                else if(ret<0)
                {
                    bignum_t t;
                    memcpy(t,num,sizeof(bignum_t));
                    memset(num,0,sizeof(bignum_t));
                    num[0]=1;
                    add(num,ABS (a));
                    sgn=-sgn;
                    sub(num,t);
                }
                else memset(num,0,sizeof(bignum_t)),num[0]=1,sgn=0 ;
            }
            else if(!sgn) sgn=SGN(a),add(num,ABS(a));
            return*this;
        }
        inline bigint operator+(const bigint&a)
        {
            bigint ret;
            memcpy(ret.num,num,sizeof(bignum_t));
            ret.sgn=sgn;
            ret+=a;
            return ret;
        }
        inline bigint operator+(const ll a)
        {
            bigint ret;
            memcpy(ret.num,num,sizeof (bignum_t));
            ret.sgn=sgn;
            ret+=a;
            return ret;
        }
        inline bigint&operator-=(const bigint&a)
        {
            if(sgn*a.sgn<0)add(num,a.num);
            else if(sgn&&a.sgn)
            {
                ll ret=comp(num,a.num);
                if(ret>0)sub(num,a.num);
                else if(ret<0)
                {
                    bignum_t t;
                    memcpy(t,num,sizeof(bignum_t));
                    memcpy(num,a.num,sizeof(bignum_t));
                    sub(num,t);
                    sgn=-sgn;
                }
                else memset(num,0,sizeof(bignum_t)),num[0]=1,sgn=0;
            }
            else if(!sgn)add(num,a.num),sgn=-a.sgn ;
            return*this ;
        }
        inline bigint&operator-=(const ll a)
        {
            if(sgn*a<0)add(num,ABS(a));
            else if(sgn&&a)
            {
                ll ret=comp(num,ABS(a));
                if(ret>0)sub(num,ABS(a));
                else if(ret<0)
                {
                    bignum_t t;
                    memcpy(t,num,sizeof(bignum_t));
                    memset(num,0,sizeof(bignum_t));
                    num[0]=1;
                    add(num,ABS(a));
                    sub(num,t);
                    sgn=-sgn;
                }
                else memset(num,0,sizeof(bignum_t)),num[0]=1,sgn=0;
            }
            else if(!sgn)sgn=-SGN(a),add(num,ABS(a));
            return*this ;
        }
        inline bigint operator-(const bigint&a)
        {
            bigint ret;
            memcpy(ret.num,num,sizeof(bignum_t));
            ret.sgn=sgn;
            ret-=a;
            return ret;
        }
        inline bigint operator-(const ll a)
        {
            bigint ret;
            memcpy(ret.num,num,sizeof(bignum_t));
            ret.sgn=sgn;
            ret-=a;
            return ret;
        }
        inline bigint&operator*=(const bigint&a)
        {
            bignum_t t;
            mul(t,num,a.num);
            memcpy(num,t,sizeof(bignum_t));
            sgn*=a.sgn;
            return*this;
        }
        inline bigint&operator*=(const ll a)
        {
            mul(num,ABS(a));
            sgn*=SGN(a);
            return*this;
        }
        inline bigint operator*(const bigint&a)
        {
            bigint ret;
            mul(ret.num,num,a.num);
            ret.sgn=sgn*a.sgn ;
            return ret;
        }
        inline bigint operator*(const ll a)
        {
            bigint ret;
            memcpy(ret.num,num,sizeof(bignum_t));
            mul(ret.num,ABS(a));
            ret.sgn=sgn*SGN(a);
            return ret;
        }
        inline bigint&operator/=(const bigint&a)
        {
            bignum_t t;
            div(t,num,a.num);
            memcpy (num,t,sizeof(bignum_t));
            sgn=(num[0]==1&&!num[1])?0:sgn*a.sgn ;
            return*this;
        }
        inline bigint&operator/=(const ll a)
        {
            ll t;
            div(num,ABS(a),t);
            sgn=(num[0]==1&&!num [1])?0:sgn*SGN(a);
            return*this;
        }
        inline bigint operator/(const bigint&a)
        {
            bigint ret;
            bignum_t t;
            memcpy(t,num,sizeof(bignum_t));
            div(ret.num,t,a.num);
            ret.sgn=(ret.num[0]==1&&!ret.num[1])?0:sgn*a.sgn ;
            return ret;
        }
        inline bigint operator/(const ll a)
        {
            bigint ret;
            ll t;
            memcpy(ret.num,num,sizeof(bignum_t));
            div(ret.num,ABS(a),t);
            ret.sgn=(ret.num[0]==1&&!ret.num[1])?0:sgn*SGN(a);
            return ret;
        }
        inline bigint&operator%=(const bigint&a)
        {
            bignum_t t;
            div(t,num,a.num);
            if(num[0]==1&&!num[1])sgn=0;
            return*this;
        }
        inline ll operator%=(const ll a)
        {
            ll t;
            div(num,ABS(a),t);
            memset(num,0,sizeof(bignum_t));
            num[0]=1;
            add(num,t);
            return t;
        }
        inline bigint operator%(const bigint&a)
        {
            bigint ret;
            bignum_t t;
            memcpy(ret.num,num,sizeof(bignum_t));
            div(t,ret.num,a.num);
            ret.sgn=(ret.num[0]==1&&!ret.num [1])?0:sgn;
            return ret;
        }
        inline ll operator%(const ll a)
        {
            bigint ret;
            ll t;
            memcpy(ret.num,num,sizeof(bignum_t));
            div(ret.num,ABS(a),t);
            memset(ret.num,0,sizeof(bignum_t));
            ret.num[0]=1;
            add(ret.num,t);
            return t;
        }
        inline ll operator>(const bigint&a)
        {
            return sgn>0?(a.sgn>0?comp(num,a.num)>0:1):(sgn<0?(a.sgn<0?comp(num,a.num)<0:0):a.sgn<0);
        }
        inline ll operator>(const ll a)
        {
            return sgn>0?(a>0?comp(num,a)>0:1):(sgn<0?(a<0?comp(num,-a)<0:0):a<0);
        }
        inline ll operator>=(const bigint&a)
        {
            return sgn>0?(a.sgn>0?comp(num,a.num)>=0:1):(sgn<0?(a.sgn<0?comp(num,a.num)<=0:0):a.sgn<=0);
        }
        inline ll operator>=(const ll a)
        {
            return sgn>0?(a>0?comp(num,a)>=0:1):(sgn<0?(a<0?comp(num,-a)<=0:0):a<=0);
        }
        inline ll operator<(const bigint&a)
        {
            return sgn<0?(a.sgn<0?comp(num,a.num)>0:1):(sgn>0?(a.sgn>0?comp(num,a.num)<0:0):a.sgn>0);
        }
        inline ll operator<(const ll a)
        {
            return sgn<0?(a<0?comp(num,-a)>0:1):(sgn>0?(a>0?comp(num,a)<0:0):a>0);
        }
        inline ll operator<=(const bigint&a)
        {
            return sgn<0?(a.sgn<0?comp(num,a.num)>=0:1):(sgn>0?(a.sgn>0?comp(num,a.num)<=0:0):a.sgn>=0);
        }
        inline ll operator<=(const ll a)
        {
            return sgn<0?(a<0?comp(num,-a)>=0:1):(sgn>0?(a>0?comp(num,a)<=0:0):a>=0);
        }
        inline ll operator==(const bigint&a)
        {
            return(sgn==a.sgn)?!comp(num,a.num):0;
        }
        inline ll operator==(const ll a)
        {
            return(sgn*a>=0)?!comp(num,ABS(a)):0;
        }
        inline ll operator!=(const bigint&a)
        {
            return(sgn==a.sgn)?comp(num,a.num):1 ;
        }
        inline ll operator!=(const ll a)
        {
            return(sgn*a>=0)?comp(num,ABS(a)):1 ;
        }
        inline ll operator[](const ll a)
        {
            return digit(num,a);
        }
        friend inline istream&operator>>(istream&is,bigint&a)
        {
            read(a.num,a.sgn,is);
            return is;
        }
        friend inline ostream&operator<<(ostream&os,const bigint&a)
        {
            if(a.sgn<0) os<<'-';
            write(a.num,os);
            return os;
        }
        friend inline bigint sqrt(const bigint&a)
        {
            bigint ret;
            bignum_t t;
            memcpy(t,a.num,sizeof(bignum_t));
            sqrt(ret.num,t);
            ret.sgn=ret.num[0]!=1||ret.num[1];
            return ret;
        }
        friend inline bigint sqrt(const bigint&a,bigint&b)
        {
            bigint ret;
            memcpy(b.num,a.num,sizeof(bignum_t));
            sqrt(ret.num,b.num);
            ret.sgn=ret.num[0]!=1||ret.num[1];
            b.sgn=b.num[0]!=1||ret.num[1];
            return ret;
        }
        inline ll length()
        {
            return :: length(num);
        }
        inline ll zeronum()
        {
            return :: zeronum(num);
        }
    };
     
    int main()
    {
        int n,i;
        bigint x,ans;
        while(~scanf("%d",&n))
        {
            ans=1;
            for(i=0;i<n;i++)
            {
                cin>>x;
                ans=ans*x;
            }
            cout<<ans<<"
    ";
        }
        return 0;
    }
    成功的路并不拥挤,因为大部分人都在颓(笑)
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  • 原文地址:https://www.cnblogs.com/SuuT/p/8909987.html
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