HDU 5804 Price List

题目链接：

http://acm.hdu.edu.cn/showproblem.php?pid=5804

Problem Description

There are n shops numbered with successive integers from 1 to n in Byteland. Every shop sells only one kind of goods, and the price of the i-th shop's goods is vi.

Every day, Byteasar will purchase some goods. He will buy at most one piece of goods from each shop. Of course, he can also choose to buy nothing. Back home, Byteasar will calculate the total amount of money he has costed that day and write it down on his account book.

However, due to Byteasar's poor math, he may calculate a wrong number. Byteasar would not mind if he wrote down a smaller number, because it seems that he hadn't used too much money.

Please write a program to help Byteasar judge whether each number is sure to be strictly larger than the actual value.

 

 

Input

The first line of the input contains an integer T (1≤T≤10), denoting the number of test cases.

In each test case, the first line of the input contains two integers n,m (1≤n,m≤100000), denoting the number of shops and the number of records on Byteasar's account book.

The second line of the input contains n integers v1,v2,...,vn (1≤vi≤100000), denoting the price of the i-th shop's goods.

Each of the next m lines contains an integer q (0≤q≤1018), denoting each number on Byteasar's account book.

 

 

Output

For each test case, print a line with m characters. If the i-th number is sure to be strictly larger than the actual value, then the i-th character should be '1'. Otherwise, it should be '0'.

 

 

Sample Input

1

3 3

2 5 4

1

7

10000

Hint:

题意：

在Byteland一共有nn家商店，编号依次为11到nn。每家商店只会卖一种物品，其中第ii家商店的物品单价为v_iv​i​​。

Byteasar每天都会进行一次购物，他会在每家商店购买最多一件物品，当然他也可以选择什么都不买。回家之后，Byteasar会把这一天购物所花的钱的总数记录在账本上。

Byteasar的数学不好，他可能会把花的钱记少，也可能记多。Byteasar并不介意记少，因为这样看上去显得自己没花很多钱。

请写一个程序，帮助Byteasar判断每条记录是否一定记多了。

题解：
求出所有数的和sumsum，如果q > sumq>sum那么肯定记多了。
代码：

#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
const int maxn = 1e5+10;
#define ll long long
char s[maxn];
int main()
{
    int t;
    scanf("%d",&t);
    while(t--)
    {
        int n,m;
        ll sum=0;
        scanf("%d%d",&n,&m);
        for(int i=0;i<n;i++)
        {
            ll num;
            scanf("%lld",&num);
            sum+=num;
        }
        for(int i=0;i<m;i++)
        {
            ll num1;
            scanf("%lld",&num1);
            if(num1>sum)
                s[i]='1';
            else
                s[i]='0';
        }
        printf("%s
",s);
    }
}