zoukankan      html  css  js  c++  java
  • UVALive 6821 Automated Checking Machine

     题目链接:

    https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=4833

    The Internet Computer Parts Company (ICPC) is an on-line shop that sells computer parts. Pairs of in-line electrical connectors are among the most popular parts that ICPC sells. However, they are also one of the parts that are returned more often by unsatisfied customers, because due to errors in packaging the connectors sent to the costumers may not be compatible.

    An in-line connector is composed of five connection points, labelled from 1 to 5. Each connection point of a connector can be either a plug or an outlet. We say two connectors are compatible if, for every label, one connection point is a plug and the other connection point is an outlet (in other words, two connectors are compatible if, for every connection point with the same label, a plug and an outlet meet when the two connectors are connected).

    The figure below shows examples of two connectors that are compatible and two connectors that are not compatible.

    ICPC is introducing a state-of-the-art Automated Checking Machine (ACM), with an optical checker, which will verify whether the two connectors packaged for a customer are indeed compati- ble. The complex and expensive hardware of the ACM is ready, but they need your help to finish the software.

    Given the descriptions of a pair of in-line connectors, your task is to determine if the connectors are compatible.

    Input

    The input contains several test cases; each test case is formatted as follows. The first line contains five integers Xi (0 ≤ Xi ≤ 1 for i = 1, 2, . . . , 5), representing the connection points of the first connector in the pair. The second line contains five integers Yi (0 ≤ Yi ≤ 1 for i = 1, 2, . . . , 5), representing the connection points of the second connector. In the input, a ‘0’ represents an outlet an a ‘1’ represents a plug.

    Output

    For each test case in the input, output a line with a character representing whether the connectors are compatible or not. If they are compatible write the uppercase letter ‘Y’; otherwise write the uppercase letter ‘N’.

    Sample Input

    11010

    00101

    10010

    10110

    Sample Output

    Y

    Hint:

    题意:

    给你几个数,让你看是不是相同,相同的话输出N,其他情况就输出Y。

    题解:

    水题,直接模拟即可。

    代码:

    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    #define met(a,b) memset(a,b,sizeof(a))
    int a[5],b[5];
    int main()
    {
        while(scanf("%d",&a[0])!=EOF)
        {
        for(int i=1;i<5;i++)
            scanf("%d",&a[i]);
        for(int i=0;i<5;i++)
            scanf("%d",&b[i]);
        int flag=1;
        for(int i=0;i<5;i++)
        {
            if(a[i]==b[i])
                flag=0;
        }
        if(flag)
            printf("Y
    ");
        else
            printf("N
    ");
        }
    }
    
  • 相关阅读:
    程灵素:我走过山的时候山不说话
    编译原理自学计划
    由一个虚构的例子谈谈中小型研发型项目的技术管理及成本控制(全文)
    用3种IDE导入Linux 2.26 内核源码
    Web风行者的设计方案与计划
    使用pyste自动生成c++类的python wrapper
    让log4cpp日志文件超过2G(Linux下)的方法
    python绑定c++程序
    网络风行者(KSpider)的规则体系结构
    检测您的浏览器是否支持 HTML5 视频方法
  • 原文地址:https://www.cnblogs.com/TAT1122/p/5846441.html
Copyright © 2011-2022 走看看