python子类分配

原问题是将左边样式变成右边样式：

即有父类和子类，父类包括多个子类，怎样将子类匹配到父类下面的问题

代码如下

#!/usr/bin/python3.4
# -*- coding: utf-8 -*-

arr1 = ["S01","S01","S01","S02","S03","S04","S04"]
arr2 = ["G0001","G0002","G0003","G0004","G0003","G0004","G0005"]
# 用来存放父类
father = []
# 放入第一个单方便后面循环计算
father.append(arr1[0])
# 子类
son = []
# 临时数组
temp = []

for i in range(0,len(arr1)):
    # 如果father里面存在，就跳过
    # 把子类存入临时数组
    if arr1[i] in father:
        temp.append(arr2[i])
        pass
    # 如果father里面不存在
    # 释放临时数组
    else:
        son.append(temp)
        temp = []
        father.append(arr1[i])
        temp.append(arr2[i])
# 将最后一次循环的temp放入son
son.append(temp)
print(father)
print(son)

运行效果：