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  • hdu5832 A water problem

    A water problem

    Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
    Total Submission(s): 342    Accepted Submission(s): 187


    Problem Description
    Two planets named Haha and Xixi in the universe and they were created with the universe beginning.

    There is 73 days in Xixi a year and 137 days in Haha a year.

    Now you know the days N after Big Bang, you need to answer whether it is the first day in a year about the two planets.
     
    Input
    There are several test cases(about 5 huge test cases).

    For each test, we have a line with an only integer N(0N) , the length of N is up to 10000000 .
     
    Output
    For the i-th test case, output Case #i: , then output "YES" or "NO" for the answer.
     
    Sample Input
    10001 0 333
     
    Sample Output
    Case #1: YES Case #2: YES Case #3: NO
     
    Author
    UESTC
     
    Source
     
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    解题思路:判断输入的数能否被10001整除,因为10001是73和137的最小公倍数。
      只要模拟除法,看最后的余数就可以。
      因为判断位数太多,所以也不能用java大数做,不然会内存超限。
      感觉之前做题给做傻了,一见到大数就想用java,一看别人说的题意就理解了,但自己看就是看不懂题意。
    代码:
     1 #include <iostream>
     2 #include <cstdio>
     3 #include <cstring>
     4 
     5 using namespace std;
     6 
     7 char s[10000005];
     8 
     9 int main()
    10 {
    11     int z=1;
    12     int ans=0;
    13     int d=10001;
    14     int len;
    15     while(scanf("%s",s)!=EOF){
    16         ans=0;
    17         len=strlen(s);
    18         for(int i=0;i<len;i++){
    19             ans=((ans*10+(s[i]-'0'))%d)%d;
    20         }
    21         if(ans==0){
    22             printf("Case #%d: YES
    ",z++);
    23         }else{
    24             printf("Case #%d: NO
    ",z++);
    25         }
    26     }
    27     return 0;
    28 }
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  • 原文地址:https://www.cnblogs.com/TWS-YIFEI/p/5771733.html
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