判断身份证：要么是15位，要么是18位，最后一位可以为字母，并写程序提出其中的年月日 （正则表达式）

package com.test;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class ID {
	public static void main(String[] args) {
		String[] strs = { "130681198712092019", "13068119871209201x", "13068119871209201", "123456789012345",
				"12345678901234x", "1234567890123" };
		Pattern p1 = Pattern.compile("(\d{17}[0-9a-zA-Z]|\d{14}[0-9a-zA-Z])");
		for (int i = 0; i < strs.length; i++) {
			Matcher matcher = p1.matcher(strs[i]);
			System.out.println(strs[i] + ":" + matcher.matches());
		}
		Pattern p2 = Pattern.compile("\d{6}(\d{8}).*"); // 用于提取出生日字符串
		Pattern p3 = Pattern.compile("(\d{4})(\d{2})(\d{2})");// 用于将生日字符串进行分解为年月日
		for (int i = 0; i < strs.length; i++) {
			Matcher matcher = p2.matcher(strs[i]);
			boolean b = matcher.find();
			if (b) {
				String s = matcher.group(1);
				Matcher matcher2 = p3.matcher(s);
				if (matcher2.find()) {
					System.out.println(
							"生日为" + matcher2.group(1) + "年" + matcher2.group(2) + "月" + matcher2.group(3) + "日");
				}
			}
		}
	}
}