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  • Python 案例 004 (计算当前时间是一年中的第几天)



    # -*- coding:utf-8 -*-
    
    """
    计算当前时间是一年中的第几天
    """
    
    bissextile = [31,60,91,121,152,182,213,244,274,305,335,366]    #leap year
    commonYear =[31,59,90,120,151,181,212,243,273,304,334,365]
    enterYear = int(raw_input("enter the Year :"))
    enterMonth = int(raw_input("enter the Month :"))
    enterDay = int(raw_input("enter the Day :"))
    remained = 0
    # first need to check is leap or common year
    if (enterYear%100 !=0) and (enterYear %4 == 0 ) or (enterYear%400 == 0):
        if enterMonth > 1 :
            remained = bissextile[enterMonth-1] + enterDay
        else:
            remained = enterDay
    else:
        if enterMonth > 1 :
            remained = commonYear[enterMonth-1] + enterDay
        else:
            remained = enterDay
    print remained
    
    """
    enter the Year :2014
    enter the Month :1
    enter the Day :15
    15
    
    enter the Year :2018
    enter the Month :6
    enter the Day :12
    193
    
    """
    
    '''
    还需要更严格的限制条件,才成。
    '''


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  • 原文地址:https://www.cnblogs.com/TendToBigData/p/10501228.html
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