zoukankan      html  css  js  c++  java
  • 字典树

    字典树类似于二叉树

    每一个节点中都有一个指针数组

    存的是字符串的一个字符

    字典树可以进行查找,统计计数,排序,代码如下

    typedef struct NODE
    {
        int nCount;
        char szMean[20];        //用来存字符串的,遍历的时候用
        struct NODE* pNext[26];
    }Tree;
    
    Tree* CreateTree()
    {
        Tree* ptree = (Tree*)malloc(sizeof(Tree));
        memset(ptree->pNext,0,sizeof(Tree*)*26);
        memset(ptree->szMean,0,sizeof(char)*20);
        ptree->nCount = 0;
        return ptree;
    
    }
    
    void InsertNode(Tree* pRoot,char** arr,int length)
    {
        if(pRoot == NULL || arr == NULL || length <= 0) return ;
        Tree* ptemp = NULL;
        int i;
    
        for(int j=0;j<length;j++)
        {
            i=0;
            ptemp = pRoot;
            //判断字符串到没到结尾
            while(arr[j][i] != '')
            {
                //判断根节点中对应的指针数组里有没有值
                if(ptemp->pNext[arr[j][i]-97] == NULL)
                {
                    //没有值,创建新的节点
                    Tree* tree = (Tree*)malloc(sizeof(Tree));
                    memset(tree->pNext,0,sizeof(Tree*)*26);
                    memset(tree->szMean,0,sizeof(char)*20);
                    ptemp->pNext[arr[j][i]-97] = tree;
                    tree->nCount = 0;
                    ptemp = tree;  
                }
                else
                {
                    //有值了,往下走
                    ptemp = ptemp->pNext[arr[j][i]-97];
                }
                i++;
            }
            //字符串到结尾了
            //把字符串存在结尾的这个数组里
            memcpy(ptemp->szMean,arr[j],20);
            //结尾的标志++
            ptemp->nCount++;
        }
    }
    void Bianli(Tree* tree)
    {
        if(tree == NULL) return;
    //  for(int i=0;i<26;i++)
    //      Bianli(tree->pNext[i]);
    
        //前序遍历,如果注释掉下面就是后序遍历
        for(int i=0;i<tree->nCount;i++)
            printf("%s
    ",tree->szMean);
    
        for(int i=0;i<26;i++)
            Bianli(tree->pNext[i]);
    }

     忘记写查询了....

    int Search(Tree* ptree,char* arr)
    {
        if(arr == NULL|| ptree == NULL) return -1;
        int len = strlen(arr);
        int i;
        for(i=0;i<len;i++)
        {
            if(ptree->pNext[arr[i]-97] == NULL)
                break;
            ptree = ptree->pNext[arr[i]-97];
        }
        if(i != len || ptree->nCount == 0) return -1;
        return 1;
    }
  • 相关阅读:
    SQL-W3School-高级:SQL LIKE 操作符
    SQLW3School-高级:SQL TOP 子句
    SQL-W3School-基础:SQL DELETE 语句
    SQL-W3School-基础:SQL UPDATE 语句
    SQL-W3School-基础:SQL INSERT INTO 语句
    SQL-W3School-基础:SQL ORDER BY 子句
    SQL-W3School-基础:SQL AND & OR 运算符
    SQL-W3School-基础:SQL WHERE 语句
    SQL-W3School-基础:SQL DISTINCT 语句
    SQL-W3School-基础:SQL SELECT 语句
  • 原文地址:https://www.cnblogs.com/TheQi/p/9152556.html
Copyright © 2011-2022 走看看