数组

#include<iostream>
#include<cstdio>
#include<cstdlib>
using  std::cin;
using  std::cout;
typedef int type;
typedef struct array
{
	type *base;//基址
	int index[3];//数组每维大小
	int count[3];//用于计算，储存每维的元素个数，例：每面，每行，每列的元素个数
};
//初始化三维数组，并返回是否成功
int init(array*a, int x, int y,int z)
{
	if (x < 0 || y < 0 || z < 0)return 0;
	a->index[0] = x; a->index[1] = y; a->index[2] = z;
	a->base = new int[sizeof(type)*x*y*z]; if (!a->base)return 0;
	a->count[0] = y*z; a->count[1] = z; a->count[2] = 1;
	return 1;
}
//通过num指针返回x,y,z的数组元素值，并通过函数返回是否访问成功
int Value(array*a, int x, int y, int z, int *num)
{
	if (x < 0 || x >= a->index[0] || y < 0 || y >= a->index[1] || z < 0 || z >= a->index[2])
		return -1;
	int off = x*a->count[0] + y*a->count[1] + z*a->count[2];
	*num = *(a->base + off);
	return 1;
}
//返回x,y,z位置的数组元素的值，失败返回-1..
int value(array*a, int x, int y, int z)
{
	if (x < 0 || x >= a->index[0] || y < 0 || y >= a->index[1] || z < 0 || z >= a->index[2])
		return -1;
	int off = x*a->count[0] + y*a->count[1] + z*a->count[2];
	//*num = *(a->base + off);
	return *(a->base+off);
}
//将num赋值给x,y,z位置的元素，通过函数返回是否成功
int assign(array*a, int x, int y, int z, type num)
{
	if (x < 0 || x >= a->index[0] || y < 0 || y >= a->index[1] || z < 0 || z >= a->index[2])
		return 0;
	int off = x*a->count[0] + y*a->count[1] + z*a->count[2];
	*(a->base + off) = num;
	return 1;
}

//一些乱乱的函数

//填充整个数组，用于测试
void Fill(array*a)
{
	int i, j, k, c = 0;
	for (i = 0; i < a->index[0]; i++)
		for (j = 0; j <a->index[1]; j++)
			for (k = 0; k <a->index[2]; k++, c++)
				assign(a, i, j, k, c);
}
//打印整个数组，用于测试
void Out(array*a)
{
	int i, j, k;
	for (i = 0; i < a->index[0]; i++)
	{
		for (j = 0; j < a->index[1]; j++)
		{
			for (k = 0; k < a->index[2]; k++)
			{
				printf("(%d,%d,%d):%d", i, j, k, value(a, i, j, k));
			}
			printf("
");
		}
		printf("

");
	}
}
int main()
{
	int i, j, k, c = 0;
	array a, *p = &a;
	init(p, 3, 3, 3);
	Fill(p);
	Out(p);
	
}

版权声明：本文为博主原创文章，未经博主允许不得转载。