YKT文件解析

YKT文件为二进制文件，使用notepad++的HEX-Editor打开后为

为了快速查看文件内容，用python代码解析

from struct import *

'''
大端小端问题：http://blog.csdn.net/fan_hai_ping/article/details/8424360
             http://blog.csdn.net/lis_12/article/details/52777983
'''
def ReadYKTFile():
    A3 = '<bqqhhhiibhiq'
    
    f = open(u'D:\jie\02_测试数据\YKT\20170901\52013170901000000001J0','rb')
    #<小端模式
    print unpack('<bbbhhhiibbqqqqqqqqqq',f.read(1+1+1+2+2+2+4+4+1+1+8+8+8+8+8+8+8+8+8+8))
    
    f.close()
    f = open(u'D:\jie\02_测试数据\YKT\20170901\52013170901000000001J0','rb')
    print unpack('@bbbhhhiibbqqqqqq',f.read(72))
    f.close()
    
    #print calcsize("bbbhhhiibbqqqqqqqqqq") 
    #print calcsize("<bbbhhhiibbqqqqqqqqqq") 
    print BCDtoDatetime(17372960,4) #20170901，日期格式
    print BCDtoDatetime(320869749, 4)
    
'''
BCD编码是4个bit位表示一个数字

参数：x需要转换的数字，y字节数
'''
def BCDtoDatetime(x,y):
    #s = str(bin(x))
    s = ''
    temp = ''
    for i in range(y*2):
        #print i,x
        m,n = divmod(x,pow(16,y*2-(i+1)))
        #print m,n
        x = n
        if((i)%2>0):
            temp = temp + str(m)
            #print temp
            s = str(temp)+s
            temp = ''            
        else:
            temp = str(m)
    return s