手动模拟一下就出来了
Uniform Generator
Time Limit : 2000/1000ms (Java/Other) Memory Limit : 65536/32768K (Java/Other)
Total Submission(s) : 16 Accepted Submission(s) : 6
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Problem Description
Computer simulations often require random numbers. One way to generate pseudo-random numbers is via a function of the form
seed(x+1) = [seed(x) + STEP] % MOD
where '%' is the modulus operator.
Such a function will generate pseudo-random numbers (seed) between 0 and MOD-1. One problem with functions of this form is that they will always generate the same pattern over and over. In order to minimize this effect, selecting the STEP and MOD values carefully can result in a uniform distribution of all values between (and including) 0 and MOD-1.
For example, if STEP = 3 and MOD = 5, the function will generate the series of pseudo-random numbers 0, 3, 1, 4, 2 in a repeating cycle. In this example, all of the numbers between and including 0 and MOD-1 will be generated every MOD iterations of the function. Note that by the nature of the function to generate the same seed(x+1) every time seed(x) occurs means that if a function will generate all the numbers between 0 and MOD-1, it will generate pseudo-random numbers uniformly with every MOD iterations.
If STEP = 15 and MOD = 20, the function generates the series 0, 15, 10, 5 (or any other repeating series if the initial seed is other than 0). This is a poor selection of STEP and MOD because no initial seed will generate all of the numbers from 0 and MOD-1.
Your program will determine if choices of STEP and MOD will generate a uniform distribution of pseudo-random numbers.
seed(x+1) = [seed(x) + STEP] % MOD
where '%' is the modulus operator.
Such a function will generate pseudo-random numbers (seed) between 0 and MOD-1. One problem with functions of this form is that they will always generate the same pattern over and over. In order to minimize this effect, selecting the STEP and MOD values carefully can result in a uniform distribution of all values between (and including) 0 and MOD-1.
For example, if STEP = 3 and MOD = 5, the function will generate the series of pseudo-random numbers 0, 3, 1, 4, 2 in a repeating cycle. In this example, all of the numbers between and including 0 and MOD-1 will be generated every MOD iterations of the function. Note that by the nature of the function to generate the same seed(x+1) every time seed(x) occurs means that if a function will generate all the numbers between 0 and MOD-1, it will generate pseudo-random numbers uniformly with every MOD iterations.
If STEP = 15 and MOD = 20, the function generates the series 0, 15, 10, 5 (or any other repeating series if the initial seed is other than 0). This is a poor selection of STEP and MOD because no initial seed will generate all of the numbers from 0 and MOD-1.
Your program will determine if choices of STEP and MOD will generate a uniform distribution of pseudo-random numbers.
Input
Each line of input will contain a pair of integers for STEP and MOD in that order (1 <= STEP, MOD <= 100000).
Output
For each line of input, your program should print the STEP value
right- justified in columns 1 through 10, the MOD value right-justified
in columns 11 through 20 and either "Good Choice" or "Bad Choice"
left-justified starting in column 25. The "Good Choice" message should
be printed when the selection of STEP and MOD will generate all the
numbers between and including 0 and MOD-1 when MOD numbers are
generated. Otherwise, your program should print the message "Bad
Choice". After each output test set, your program should print exactly
one blank line.
Sample Input
3 5 15 20 63923 99999
Sample Output
3 5 Good Choice
15 20 Bad Choice
63923 99999 Good Choice
AC之前你是肯定要PE的，至于几次就看你EQ了
#include<stdio.h>
#include<string.h>
#define N 100008
int main()
{
int seed[N], step, mod, i, div[N];
while(scanf("%d%d", &step, &mod) != EOF)
{
memset(div, 0, sizeof(div));
memset(seed, 0, sizeof(seed));
seed[0] = 0;
for(i = 0; i < N-1; i++)
{
seed[i+1] = (seed[i] + step) % mod;
div[seed[i+1]] = 1; // 把出现过的余数置为1；
if(seed[i+1] == seed[0])
break;
}
printf("%10d%10d", step, mod);
for(i = 0; i < mod; i++)
{
if(div[i] == 0) //看这个数是否出现过
break;
}
if(i < mod)
printf(" Bad Choice
");
else
printf(" Good Choice
");
}
}
ideas：
越来越发现so easy 了。只要你thinking~~~