题目链接:http://hihocoder.com/problemset/problem/1616
题解:就是简单的模拟一下至于如何判断是不是二叉搜索树可以通过中序遍历将每个点存下来看是不是递增的如果是递增的就是反之不是
#include <iostream> #include <cstring> #include <cstdio> #include <vector> #include <algorithm> using namespace std; const int M = 1e4 + 10; vector<int> vc[M]; int fa[M] , ch[M][2] , f[M] , n , emmm , num[M]; void init() { for(int i = 1 ; i <= n ; i++) { f[i] = i; vc[i].clear(); } } int find(int x) { if(x == f[x]) return f[x]; return f[x] = find(f[x]); } int cnt; void cau(int u) { int len = vc[u].size(); if(len == 2) { if(vc[u][0] == vc[u][1] || vc[u][0] == u || vc[u][1] == u) emmm = 1; cau(vc[u][0]); num[cnt++] = u; cau(vc[u][1]); } if(len == 1) { if(vc[u][0] == u) emmm = 1; if(vc[u][0] > u) { num[cnt++] = u; cau(vc[u][0]); } else { cau(vc[u][0]); num[cnt++] = u; } } if(len == 0) { num[cnt++] = u; } } void dfs(int u) { int len = vc[u].size(); if(len == 1) { if(u > vc[u][0]) { putchar('('); printf("%d" , vc[u][0]); dfs(vc[u][0]); putchar(')'); putchar('('); putchar(')'); } else { putchar('('); putchar(')'); putchar('('); printf("%d" , vc[u][0]); dfs(vc[u][0]); putchar(')'); } } if(len == 2) { putchar('('); printf("%d" , vc[u][0]); dfs(vc[u][0]); putchar(')'); putchar('('); printf("%d" , vc[u][1]); dfs(vc[u][1]); putchar(')'); } if(len == 0) { putchar('('); putchar(')'); putchar('('); putchar(')'); } } int main() { int t; scanf("%d" , &t); while(t--) { cnt = 0; scanf("%d" , &n); memset(fa , -1 , sizeof(fa)); int flag = 0; init(); for(int i = 1 ; i <= n - 1 ; i++) { int u , v; scanf("%d%d" , &u , &v); vc[u].push_back(v); int a = find(u) , b = find(v); if(a == b) { flag = 1; } else { f[b] = a; } if(fa[v] == -1) { fa[v] = u; continue; } else { flag = 1; } } if(flag) { printf("ERROR1 "); } else { int tmp = 0; for(int i = 1 ; i <= n ; i++) { if(vc[i].size() == 0) continue; sort(vc[i].begin() , vc[i].end()); if(vc[i].size() > 2) { tmp = 1; break; } } if(tmp) { printf("ERROR2 "); } else { emmm = 0; int root = 1; for(int i = 1 ; i <= n ; i++) { if(fa[i] == -1) { root = i; break; } } cau(root); for(int i = 1 ; i < cnt ; i++) { if(num[i] <= num[i - 1]) { emmm = 1; break; } } if(emmm) { printf("ERROR3 "); } else { putchar('('); printf("%d" , root); dfs(root); putchar(')'); puts(""); } } } } return 0; }