P3130 [USACO15DEC]计数haybalesCounting Haybales

P3130 [USACO15DEC]计数haybalesCounting Haybales

1)给定一段连续的田地，给每一个田地都增加一些新的草包。

2)给定一段连续的田地，找出草包最少的田地有多少草包。

3)给定一段连续的田地，统计一共有多少草包。

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错误日志： (pushdown) 时记录懒标记用了 (int) ， 下次（在没有把握的情况下）应全部替换

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Solution

线段树， 懒标记， 靠前练手

Code

#include<iostream>
#include<cstdio>
#include<queue>
#include<cstring>
#include<algorithm>
#include<climits>
#define LL long long
using namespace std;
LL RD(){
    LL out = 0,flag = 1;char c = getchar();
    while(c < '0' || c >'9'){if(c == '-')flag = -1;c = getchar();}
    while(c >= '0' && c <= '9'){out = out * 10 + c - '0';c = getchar();}
    return flag * out;
    }
const LL maxn = 400019;
LL num, na;
LL v[maxn];
#define lid (id << 1)
#define rid (id << 1) | 1
struct seg_tree{
	LL l, r;
	LL min, sum, lazy;
	}tree[maxn << 2];
void pushup(LL id){
	tree[id].sum = tree[lid].sum + tree[rid].sum;
	tree[id].min = min(tree[lid].min, tree[rid].min);
	}
void build(LL id, LL l, LL r){
	tree[id].l = l, tree[id].r = r;
	if(l == r){
		tree[id].min = tree[id].sum = v[l];
		return ;
		}
	LL mid = (l + r) >> 1;
	build(lid, l, mid), build(rid, mid + 1, r);
	pushup(id);
	}
void pushdown(LL id){
	if(tree[id].lazy != 0){
		LL val = tree[id].lazy;
		tree[lid].sum += val * (tree[lid].r - tree[lid].l + 1);
		tree[rid].sum += val * (tree[rid].r - tree[rid].l + 1);
		tree[lid].min += val;
		tree[rid].min += val;
		tree[lid].lazy += val;
		tree[rid].lazy += val;
		tree[id].lazy = 0;
		}
	}
void update(LL id, LL val, LL l, LL r){
	pushdown(id);
	if(tree[id].l == l && tree[id].r == r){
		tree[id].lazy += val;
		tree[id].sum += val * (tree[id].r - tree[id].l + 1);
		tree[id].min += val;
		return ;
		}
	LL mid = (tree[id].l + tree[id].r) >> 1;
	if(mid < l)update(rid, val, l, r);
	else if(mid >= r)update(lid, val, l, r);
	else update(lid, val, l, mid), update(rid, val, mid + 1, r);
	pushup(id);
	}
LL get_sum(LL id, LL l, LL r){
	pushdown(id);
	if(tree[id].l == l && tree[id].r == r){
		return tree[id].sum;
		}
	LL mid = (tree[id].l + tree[id].r) >> 1;
	if(mid < l)return get_sum(rid, l, r);
	else if(mid >= r)return get_sum(lid, l, r);
	else return get_sum(lid, l, mid) + get_sum(rid, mid + 1, r);
	}
LL get_min(LL id, LL l, LL r){
	pushdown(id);
	if(tree[id].l == l && tree[id].r == r){
		return tree[id].min;
		}
	LL mid = (tree[id].l + tree[id].r) >> 1;
	if(mid < l)return get_min(rid, l, r);
	else if(mid >= r)return get_min(lid, l, r);
	else return min(get_min(lid, l, mid), get_min(rid, mid + 1, r));
	}
int main(){
	num = RD(), na = RD();
	for(LL i = 1;i <= num;i++)v[i] = RD();
	build(1, 1, num);
	char cmd;
	while(na--){
		cin>>cmd;
		LL l = RD(), r = RD();
		if(cmd == 'M')printf("%lld
", get_min(1, l, r));
		else if(cmd == 'S')printf("%lld
", get_sum(1, l, r));
		else{
			LL val = RD();
			update(1, val, l, r);
			}
		}
	return 0;
	}