Description
Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock.
The combination lock is represented by n rotating disks with digits from 0 to 9 written on them. Scrooge McDuck has to turn some disks so that the combination of digits on the disks forms a secret combination. In one move, he can rotate one disk one digit forwards or backwards. In particular, in one move he can go from digit 0 to digit 9 and vice versa. What minimum number of actions does he need for that?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of disks on the combination lock.
The second line contains a string of n digits — the original state of the disks.
The third line contains a string of n digits — Scrooge McDuck's combination that opens the lock.
Output
Print a single integer — the minimum number of moves Scrooge McDuck needs to open the lock.
Sample Input
5 82195 64723
13
Hint
In the sample he needs 13 moves:
- 1 disk:
- 2 disk:
- 3 disk:
- 4 disk:
- 5 disk:
#include <iostream> #include <cmath> using namespace std; int main() { int n; char a[1100]; char b[1100]; int flag= 0 ; cin >> n; for (int i=0; i<n; i++) cin >> a[i]; for (int j=0; j<n; j++) cin >> b[j]; int num = 0; for (int i=0; i<n; i++) { int p1 = (int)a[i]-48; int p2 = (int)b[i]-48; int p = p1-p2; flag = abs(p); if (flag>5) flag = 10-flag; num = num +flag; } cout << num << endl; return 0; }