zoukankan      html  css  js  c++  java
  • 557. 反转字符串中的单词 III

    题目:给定一个字符串,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序。

    示例:

    输入:"Let's take LeetCode contest"
    输出:"s'teL ekat edoCteeL tsetnoc"

    1.原创

    class Solution {
    public:
        string reverseString(string ss){
            int n = ss.size();
            for (int i=0,j=n-1;i<j;++i,--j){
                swap(ss[i],ss[j]); 
            }
            return ss;
        }
        string reverseWords(string s) {
            string res;
            string temp;
            for (auto i:s){  //string对象的索引返回是char型
                if (i !=' ') //空格是char类型也就是' '而不是string类型
                    temp += i;
                else{
                    res += reverseString(temp);
                    res += ' ';
                    temp = "";
                }
            }
            res += reverseString(temp);
            return res;
    
        }
    };

    2.题解

    class Solution {
    public: 
        string reverseWords(string s) {
            int length = s.length();
            int i = 0;
            while (i < length) {
                int start = i;
                while (i < length && s[i] != ' ') {
                    i++;
                }
    
                int left = start, right = i - 1;
                while (left < right) {
                    swap(s[left], s[right]);
                    left++;
                    right--;
                }
                while (i < length && s[i] == ' ') {
                    i++;
                }
            }
            return s;
        }
    };
    
    作者:LeetCode-Solution
    链接:https://leetcode-cn.com/problems/reverse-words-in-a-string-iii/solution/fan-zhuan-zi-fu-chuan-zhong-de-dan-ci-iii-by-lee-2/
  • 相关阅读:
    Nginx + uWSGI 配置django
    django视图缓存的实现
    scrapy 资料
    scrapy 安装
    程序题做题一般步骤
    检查代码的一般步骤
    Mathematical-Analysis-I-4
    Mathematical-Analysis-I-3
    Mathematical-Analysis-I-1
    Mathematical-Analysis-I-2
  • 原文地址:https://www.cnblogs.com/USTC-ZCC/p/14473181.html
Copyright © 2011-2022 走看看