A. Find Divisible Educational Codeforces Round 57 (Rated for Div. 2)

A - Find Divisible

题意:英语翻译题，给你一个l，r区间，要求输出x，y，[x，y]在区间[l，r]中，y是x的倍数，原文中是这样写的

x divides y  x被y整除

妈蛋，不用担心，x*2超出r边界，因为题上也说了，一定存在解，原文是这样的

妈蛋

题解:左边界l，右边界l*2，妈蛋。

代码：

#include <iostream>
using namespace std;
#define int long long
signed main(){
    //cout << "Hello world!" << endl;
    int t;
    cin>>t;
    while(t--){
        int l,r;
        cin>>l>>r;
        cout<<l<<" "<<l*2<<endl;
    }
    return 0;
}

output

standard output

You are given a range of positive integers from ll to rr.

Find such a pair of integers (x,y)(x,y) that l≤x,y≤rl≤x,y≤r, x≠yx≠y and xx divides yy.

If there are multiple answers, print any of them.

You are also asked to answer TT independent queries.

Input

The first line contains a single integer TT (1≤T≤10001≤T≤1000) — the number of queries.

Each of the next TT lines contains two integers ll and rr (1≤l≤r≤9982443531≤l≤r≤998244353) — inclusive borders of the range.

It is guaranteed that testset only includes queries, which have at least one suitable pair.

Output

Print TT lines, each line should contain the answer — two integers xx and yy such that l≤x,y≤rl≤x,y≤r, x≠yx≠y and xx divides yy. The answer in the ii-th line should correspond to the ii-th query from the input.

If there are multiple answers, print any of them.

Example

input

Copy

3
1 10
3 14
1 10

output

Copy

1 7
3 9
5 10