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  • leetcode[113]Path Sum II

    Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.

    For example:
    Given the below binary tree and sum = 22,

                  5
                 / 
                4   8
               /   / 
              11  13  4
             /      / 
            7    2  5   1
    

    return

    [
       [5,4,11,2],
       [5,8,4,5]
    ]
    /**
     * Definition for binary tree
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    class Solution {
    public:
    void find(vector<vector<int>> &res, vector<int> tmp, TreeNode *root,int sum)
    {
        if(root==NULL)return;
        if(root->left==NULL&&root->right==NULL)
        {
            if(root->val==sum)
            {
                tmp.push_back(root->val);
                res.push_back(tmp);
            }
            return;
        }
        tmp.push_back(root->val);
        find(res,tmp,root->left,sum-root->val);
        find(res,tmp,root->right,sum-root->val);
    }
        vector<vector<int> > pathSum(TreeNode *root, int sum) {
            vector<vector<int>> res;
            vector<int> tmp;
            find(res,tmp,root,sum);
            return res;
        }
    };
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  • 原文地址:https://www.cnblogs.com/Vae1990Silence/p/4281308.html
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