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  • 加强版猜年龄游戏。

    '''

    1. 给定年龄,用户可以猜三次年龄

    2. 年龄猜对,让用户选择两次奖励

    3. 用户选择两次奖励后可以退出
      '''

    age = 20
    count = 0
    jiangpin_dict ={
    '1':"绿巨人",
    '2':"美国队长",
    '3':"钢铁侠",
    '4':"蜘蛛侠",
    '5':"变形金刚",
    }
    jiangpin ="""请选择想要的奖品
    1.绿巨人
    2.美国队长
    3.钢铁侠
    4.蜘蛛侠
    5.变形金刚
    """
    new_jiangpin = {}
    while count < 3:
    age_new = input("请输入你的年龄")
    if not age_new.isdigit():
    print("大哥,你猜错了,你活了这么多岁吗")
    continue
    age_new_int = int(age_new)
    if age_new_int > age:
    print("猜大了")
    elif age_new_int < age:
    print("猜小了")
    else:
    print("猜对了")
    jiangpin_count = 0
    while jiangpin_count < 2:
    print(f"奖品如下:{jiangpin}")
    jiangpin_new = input("请输入想要的奖品:")
    jiangpin1 = jiangpin_dict[jiangpin_new]
    if jiangpin1 in new_jiangpin:
    new_jiangpin[jiangpin1] += 1
    else:
    new_jiangpin [jiangpin1] = 1
    print(f"恭喜你获得:{jiangpin1}")
    jiangpin_count += 1
    print(f"全部获得的奖品:{new_jiangpin}")
    break
    count += 1

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  • 原文地址:https://www.cnblogs.com/WQ577098649/p/11529975.html
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