这题就是
LightOJ - 1236
解析去看这个把https://www.cnblogs.com/WTSRUVF/p/9185140.html
贴代码了;
#include <iostream> #include <cstdio> #include <sstream> #include <cstring> #include <map> #include <set> #include <vector> #include <stack> #include <queue> #include <algorithm> #include <cmath> #define MOD 2018 #define LL long long #define ULL unsigned long long #define maxn 10000900 #define Pair pair<int, int> #define mem(a, b) memset(a, b, sizeof(a)) #define _ ios_base::sync_with_stdio(0),cin.tie(0) //freopen("1.txt", "r", stdin); using namespace std; const int LL_INF = 0x7fffffffffffffff,INF = 0x3f3f3f3f; LL primes[maxn/10]; bool vis[maxn]; LL ans = 0; void init() { mem(vis,0); for(int i=2; i<maxn; i++) if(!vis[i]) { primes[ans++] = i; for(LL j=(LL)i*i; j<maxn; j+=i) vis[j] = 1; } } int main() { init(); LL n; while(cin>> n && n) { LL res = 1, cnt = 0; LL temp = n; for(LL i=0; i<ans && primes[i] * primes[i] <= n; i++) { LL cnt2 = 0; while(n % primes[i] == 0) { n /= primes[i]; cnt2++; } if(cnt2 > 0) { res *= (2*cnt2 + 1); } } if(n > 1) { res *= 3; } printf("%lld %lld ",temp,res/2+1); } return 0; }