(JAVA对进制的运算)A + B Again hdu2057 要复习

（置顶，复习）A + B Again

链接：http://acm.hdu.edu.cn/showproblem.php?pid=2057

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 35905    Accepted Submission(s): 14614

Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

 

Input

The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

 

Output

For each test case,print the sum of A and B in hexadecimal in one line.

 

Sample Input

+A -A

+1A 12

1A -9

-1A -12

1A -AA

 

Sample Output

0

2C

11

-2C

-90

 

Author

linle

 

注：

此题就是利用Long.parseLong()和Long.toHexString（）的

replaceAll("\+","")，是去除其中的‘+’，因为进制计算不支持带“+”的某一进制的数字字符串，‘-’可以，同时还需要判断正数负数，从而利用Long.toHexString（）。

 

Java代码：

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner inScanner = new Scanner(System.in);
        while(inScanner.hasNext()) {
            long l = Long.parseLong(inScanner.next().replaceAll("\+", ""),16)
                    + Long.parseLong(inScanner.next().replaceAll("\+", ""),16);
            if(l<0) {
                System.out.println("-" + Long.toHexString(-l).toUpperCase());
            }
            else {
                System.out.println(Long.toHexString(l).toUpperCase());
            }
        }
    }
}