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  • DES算法

    python3可直接调用pyDes库,这里不做详细介绍

    下载及简介地址:https://twhiteman.netfirms.com/des.html

    如需要在python中使用des加密,可以直接使用pyDes库加密,该库提供了CBC和ECB两种加密方式。

    下面是C语言编写的DES算法,没有VC++6.0的同学点这安装

    1、熟悉和掌握对称加密算法的原理及其一般过程;

    2、掌握对称加密算法的基本方法:DES;

    3、掌握使用一定的编码开发工具(对具体的开发平台和工具不作要求)。

     

    VC++6.0

    第一步第一步:变换明文。对给定的64位比特的明文x,首先通过一个置换   IP表来重新排列x,从而构造出64位比特的x0x0=IP(x)=L0R0,其中L0表示x0的前32比特,R0表示x0的后32位。

     

          第二步:按照规则迭代。规则为

    Li = Ri-1

    Ri = Lif(Ri-1,Ki)   i=1,2,3…16

                 经过第一步变换已经得到L0R0的值,其中符号表示的数学运算是异或,f表示一种置换,由S盒置换构成,Ki是一些由密钥编排函数产生的比特块。fKi将在后面介绍。

     

    第三步:对L16R16利用IP-1作逆置换,就得到了密文y

     

    16轮循环:DES对经过初始置换的64位明文进行16轮类似的子加密过程。每一轮的子加密过程要经过DES的f函数,其过程如下:

         将64位明文在中间分开,划分为2部分,每部分32位,左半部分记为L,右半部分记为R,以下的操作都是对右半部分数据进行的。

          扩展置换:扩展置换将32位的输入数据根据扩展置换表扩展成为48位的输出数据。

          异或运算:将48位的明文数据与48位的子密钥进行异或运算(48位子密钥的产生过程在实验原理八.子密钥产生过程中有详细讨论)。

          S盒置换:S盒置换是非线性的,48位输入数据根据S盒置换表置换成为32位输出数据。

          直接置换:S盒置换后的32位输出数据根据直接置换表进行直接置换。

          经过直接置换的32位输出数据与本轮的L部分进行异或操作,结果作为下一轮子加密过程的R部分。本轮的R部分直接作为下一轮子加密过程的L部分。然后进入下一轮子加密过程,直到16轮全部完成。

     

    DES,一种对称加密算法,算法运算速度快,资源消耗较少;但是安全性低。

     

    在DES密钥Key的使用、管理及密钥更换的过程中,应绝对避开DES算法的应用误区,即绝对不能把Key的第8,16,24,…,64位作为有效数据位来对Key进行管理,这一点,对应用DES加密的用户来说要高度重视。

     

    有些网络,利用定期更换DES密钥Key的办法来进一步提高系统的安全性和可靠性,如果忽略了上述应用误区,那么,更换新密钥将是徒劳的,对网络的安全运行将十分危险,所以更换密钥一定要保证新Key与旧Key真正的不同,即除了第8,16,24,…,64位以外其他位数据发生了变化,这一点是非常重要的。 

     

     

     

    附录

    #include<stdio.h>

     

    /*各种函数定义*/

    int move_num(int r);

    void xor(int *r_b, int *k3, int large);

    void s_box(int r_t[32], int r_b[48]);

    void erzhuanshiliu(int *k, char *key, int large);

    void shizhuaner(int *k, int n, int i, int large);

    void round(int r, int k2[56], int k3[48], int r_s[32], int r_b[48], int l[32], int k_c_two[48], int m_c_two[32], int e[48], char c_r[8], char c_l[8]);

    void exchange(int *k1, int *k2, int *rule, int n);

    void key_move(int k2[56], int n);

     

    /*十进制转换成二进制*/

    void shizhuaner(int *k, int n, int i,int large) 

    /* k是存放二进制的数组,n是需要进行转换的十进制数,i是第i个十进制数,large是数组大小*/

    {

           int j;      //计数的j,没什么大的含义

           large = large / 8;

           j = large - 1;

           do

           {

                  k[i * large + j] = n % 2;

                  n = n / 2;

                  j--;

           } while (n != 0);

           while (j >= 0)

           {

                  k[i * large + j] = 0;

                  j--;

           }

           return ;

    }

     

    /*二进制转换成十六进制*/

    void erzhuanshiliu(int *k,char *key, int large)

    /* k是二进制数组,key是存放十六进制的数组,largek数组的大小*/

    {

           int i,j; //计数的ij,没什么大的含义

           large = large / 4;

           for (i = 0; i < large; i++)

           {

                  j = k[i * 4] * 8 + k[i * 4 + 1] * 4 + k[i * 4 + 2] * 2 + k[i * 4 + 3];

                  if (j >= 10)

                  {

                         switch (j)

                         {

                         case 10:key[i] = 'a'; break;

                         case 11:key[i] = 'b'; break;

                         case 12:key[i] = 'c'; break;

                         case 13:key[i] = 'd'; break;

                         case 14:key[i] = 'e'; break;

                         case 15:key[i] = 'f'; break;

                         }

                  }

                  else

                  {

                         j = j + 48;

                         key[i] = (char)j;

                  }

           }

           return;

    }

     

    /*循环函数*/

    void round(int r, int k2[56], int k3[48], int r_s[32], int r_b[48], int l[32], int k_c_two[48], int m_c_two[32], int e[48], char c_r[8], char c_l[8])

    /* r是轮数*/

    /* k2是密钥经过置换1置换完的数组,k3是密钥经过置换2置换完的数组*/

    /* r_s是明文处理中R32大小时的数组,r_b是明文处理中R48大小时的数组,l是明文处理中L的数组*/

    /* k_c_two是密钥处理中置换2的置换规则数组,m_c_two是明文处理中置换2的置换规则数组,e是明文处理中e盒的置换规则数组*/

    /* c_r是各轮密文的r部分,c_l是各轮密文的l部分*/

    {

           int i, n, r_t[32],r_c[32]; //计数的i,没什么大的含义;n存储该轮左移的数值;r_t,r_c存放中间处理数值的32大小的数组

           printf("这是第%d轮密文: ", r);

           n = move_num(r); //获取第r轮密钥左移的位数

           key_move(k2, n); //调用密钥左移函数

           exchange(k2, k3, k_c_two, 48);  //密钥进行置换2运算

           exchange(r_s, r_b,e,48);  //明文进行e盒扩展置换运算

           xor(r_b, k3,48);  //经过密钥置换2运算后的子密钥与从e盒出来的子明文异或 

           s_box(r_t,r_b);  //调用明文处理中的s盒运算函数

           exchange(r_t, r_c, m_c_two, 32);  //明文进行置换2运算

           for (i = 0; i < 32; i++)

                  r_t[i] = r_c[i];

           xor(r_t, l, 32);     //经过处理后的RL异或

           for (i = 0; i < 32; i++)

                  l[i] = r_s[i];  //准备下次循环的L

        for (i = 0; i < 32; i++)

                  r_s[i] = r_t[i];  //准备下次循环的R

           erzhuanshiliu(r_s, c_r, 32);

           for (i = 0; i < 8; i++)

                  printf("%c ", c_r[i]);  //rR部分的密文

           erzhuanshiliu(l, c_l, 32);

           for (i = 0; i < 8; i++)

                  printf("%c ", c_l[i]);  //rL部分的密文

           printf(" ");

           printf(" ");

           return;

    }

     

     

    /* 异或函数 */

    void xor(int *r_b, int *k3,int large)

    {

           int i;  //计数的i,没什么大的含义

           for (i = 0; i < large; i++)

           {

                  if (r_b[i] != k3[i])  //两数相同结果取0,两数不同取1

                         r_b[i] = 1;

                  else

                         r_b[i] = 0;

           }

    }

     

    /* S盒运算函数 */

    void s_box(int r_t[32],int r_b[48])

    {

           int i,hang,lie,jie;  //计数的i,没什么大的含义;hangS盒的行下标;lieS盒的列下标;jie是根据行、列下标查询出的结果

           /* S1~S8 */

           int s1[4][16] = { { 14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7 },

                             { 0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8 },

                             { 4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0 },

                             { 15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13 } },

               s2[4][16] = { { 15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10 },

                             { 3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5 },

                             { 0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15 },

                             { 13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9 } },

               s3[4][16] = { { 10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8 },

                             { 13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1 },

                             { 13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7 },

                             { 1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12 } },

               s4[4][16] = { { 7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15 },

                             { 13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9 },

                             { 10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 3 },

                             { 3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14 } },

               s5[4][16] = { { 2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9 },

                             { 14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6 },

                             { 4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14 },

                             { 11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3 } },

               s6[4][16] = { { 12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11 },

                             { 10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8 },

                             { 9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6 },

                             { 4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13 } },

               s7[4][16] = { { 4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1 },

                             { 13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6 },

                             { 1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2 },

                             { 6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12 } },

               s8[4][16] = { { 13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7 },

                             { 1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2 },

                             { 7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8 },

                             { 2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11 } };

           for (i = 0; i < 8; i++)

           {

                  hang = r_b[i * 6] * 2 + r_b[i * 6 + 5];  //0位与第5位决定行下标

                  lie = r_b[i * 6 + 1] * 8 + r_b[i * 6 + 2] * 4 + r_b[i * 6 + 3] * 2 + r_b[i * 6 + 4];  //1234位决定列下标

                  switch (i)  //i个数查询Si

                  {

                  case 0:jie = s1[hang][lie]; break;

                  case 1:jie = s2[hang][lie]; break;

                  case 2:jie = s3[hang][lie]; break;

                  case 3:jie = s4[hang][lie]; break;

                  case 4:jie = s5[hang][lie]; break;

                  case 5:jie = s6[hang][lie]; break;

                  case 6:jie = s7[hang][lie]; break;

                  case 7:jie = s8[hang][lie]; break;

                  }

                  shizhuaner(r_t, jie, i,32);  //S盒为十六进制,须转换回二进制进行存放

           }

    }

     

    /*左移函数*/

    void key_move(int k2[56], int n)

    {

           int i, one, two, twentyeight, twentynight;  //计数的i,没什么大的含义;onetwotwentyeighttwentynight用于存放第122829个数

           one = k2[0];  //先记录第122829个数

           two = k2[1];

           twentyeight = k2[28];

           twentynight = k2[29];

           for (i = 0; i < (28 - n); i++)  //循环赋值

           {

                  k2[i] = k2[i + n];

                  k2[i + 28] = k2[i + n + 28];

           }

           if (n == 1)  //左移1位时,特殊端点值(第2755)赋值

           {

                  k2[27] = one;

                  k2[55] = twentyeight;

           }

           else  //左移2位时,特殊端点值(第27285455)赋值

           {

                  k2[26] = one;

                  k2[27] = two;

                  k2[54] = twentyeight;

                  k2[55] = twentynight;

           }     

    }

     

    /* 获取第r轮左移位数 */

    int move_num(int r)

    {

           int i;  //i存储移动的位数

           switch (r)

           {

           case 1:i = 1; break;

           case 2:i = 1; break;

           case 3:i = 2; break;

           case 4:i = 2; break;

           case 5:i = 2; break;

           case 6:i = 2; break;

           case 7:i = 2; break;

           case 8:i = 2; break;

           case 9:i = 1; break;

           case 10:i = 2; break;

           case 11:i = 2; break;

           case 12:i = 2; break;

           case 13:i = 2; break;

           case 14:i = 2; break;

           case 15:i = 2; break;

           case 16:i = 1; break;

           }

           return i;  //返回移动的位数

    }

     

    /* 置换函数 */

    void exchange(int *k1, int *k2, int *rule,int n)

    {

           int i, j;  //计数的ij

           for (i = 0; i < n; i++)

           {

                  j = rule[i];     //根据rule数组进行置换,也就是赋值

                  k2[i] = k1[j-1];

           }

           return;

    }

     

    /*主函数*/

    int main()

    {

           /* c是最终密文,c_r是密文的R部分,c_l是密文的L的部分,g是用于缓冲掉回车符,k接收从键盘输入密钥,m接收从键盘输入的明文*/

           char c[16],c_r[8],c_l[8], g, k[8], m[8];

           /* 计数的ijr是轮数;n接收类型转换后的结果;k1k2k3是密钥处理中不同大小的数组;m1m2是明文处理中的数组,r_sR 32大小时的数组,r_bR 48大小时的数组,lL的数组*/

           int i, j, r, n, k1[64], k2[56], k3[48], m1[64], m2[64],r_s[32],r_b[48],l[32];

           /* k_c_one是密钥处理的置换1k_c_two是密钥处理的置换2m_c_one是明文处理的置换1e是明文处理的e盒,m_c_two是明文处理的置换2 */

           int k_c_one[56] = { 57, 49, 41, 33, 25, 17, 9,

                                  1, 58, 50, 42, 34, 26, 18,

                                  10, 2, 59, 51, 43, 35, 27,

                                  19, 11, 3, 60, 52, 44, 36,

                                  63, 55, 47, 39, 31, 23, 15,

                                  7, 62, 54, 46, 38, 30, 22,

                                  14, 6, 61, 53, 45, 37, 29,

                                  21, 13, 5, 28, 20, 12, 4 },

                  k_c_two[48] = { 14, 17, 11, 24, 1, 5,

                                  3, 28, 15, 6, 21, 10,

                                  23, 19, 12, 4, 26, 8,

                                              16, 7, 27, 20, 13, 2,

                                              41, 52, 31, 37, 47, 55,

                                              30, 40, 51, 45, 33, 48,

                                              44, 49, 39, 56, 34, 53,

                                              46, 42, 50, 36, 29, 32 },

                  m_c_one[64] = { 58, 50, 42, 34, 26, 18, 10, 2,

                                              60, 52, 44, 36, 28, 20, 12, 4,

                                              62, 54, 46, 38, 30, 22, 14, 6,

                                              64, 56, 48, 40, 32, 24, 16, 8,

                                              57, 49, 41, 33, 25, 17, 9, 1,

                                              59, 51, 43, 35, 27, 19, 11, 3,

                                              61, 53, 45, 37, 29, 21, 13, 5,

                                              63, 55, 47, 39, 31, 23, 15, 7 },

                  e[48] = { 32, 1, 2, 3, 4, 5,

                                  4, 5, 6, 7, 8, 9,

                                  8, 9, 10, 11, 12, 13,

                                  12, 13, 14, 15, 16, 17,

                                  16, 17, 18, 19, 20, 21,

                                  20, 21, 22, 23, 24, 25,

                                  24, 25, 26, 27, 28, 29,

                            28, 29, 30, 31, 32, 1 },

                  m_c_two[32] = { 16, 7, 20, 21,

                                              29, 12, 28, 17,

                                              1, 15, 23, 26,

                                              5, 18, 31, 10,

                                              2, 8, 24, 14,

                                              32, 27, 3, 9,

                                              19, 13, 30, 6,

                                              22, 11, 4, 25 },

             m_c_three[64] = { 40, 8, 48, 16, 56, 24, 64, 32,

                                              39, 7, 47, 15, 55, 23, 63, 31,

                                              38, 6, 46, 14, 54, 22, 62, 30,

                                              37, 5, 45, 13, 53, 21, 61, 29,

                                              36, 4, 44, 12, 52, 20, 60, 28,

                                              35, 3, 43, 11, 51, 19, 59, 27,

                                              34, 2, 42, 10, 50, 18, 58, 26,

                                              33, 1, 41, 9, 49, 17, 57, 25 };

           printf("******DES加密****** ");

           printf(" ");

           printf("请输入加密的密钥: ");

           for (i = 0; i < 8; i++)  //从键盘里获取输入的密钥

           {

                  scanf("%c", &k[i]);

                  n = (int)k[i];

                  shizhuaner(k1, n, i,64);  //进行密钥进制转换

           }

           g = getchar();  //缓冲掉多于8个字符以外字符和回车符

           while (g != ' ')

           {

                  g = getchar();

           }

           printf("请输入需要加密的明文: ");

           for (i = 0; i < 8; i++)  //从键盘里获取输入的明文

           {

                  scanf("%c", &m[i]);

                  n = (int)m[i];

                  shizhuaner(m1, n, i,64);  //进行明文进制转换

           }

           g = getchar();  //缓冲掉多于8个字符以外字符和回车符

           while (g != ' ')

           {

                  g = getchar();

           }

           printf(" ");

           exchange(k1, k2, k_c_one, 56);  //密钥进行置换1处理

           exchange(m1, m2, m_c_one, 64);  //明文进行密钥1处理

           for (i = 0; i < 32; i++)

                  l[i] = m2[i];  //明文的L部分

           j = 0;

           for (i = 32; i < 64; i++)

           {

                  r_s[j] = m2[i];  //明文的R部分

                  j++;

           }     

           for (r = 1; r <= 16; r++)  //进行16轮的循环处理

                  round(r,k2, k3, r_s, r_b, l, k_c_two, m_c_two, e,  c_r, c_l);

           for (i = 0; i < 64; i++)  //将密文R的部分与密文L的部分合一起

           {

                  m1[i] = r_s[i];

                  if (i >= 32)

                         m1[i] = l[i - 32];

           }

           exchange(m1, m2, m_c_three, 64);  //进行明文处理的置换3

           erzhuanshiliu(m2, c, 64);  //二进制转换成十六进制,得到最终密文

           printf("这是最终密文: ");

           for (i = 0; i < 16; i++)

                  printf("%c ", c[i]);

           printf(" ");

           return 0;

    }

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  • 原文地址:https://www.cnblogs.com/WhiteHatKevil/p/10095208.html
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