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  • SP5971 LCMSUM

    题目链接

    [egin{aligned} sumlimits_{i=1}^n [i,n]&= nsumlimits_{i=1}^n frac{i}{(i,n)}\ &= nsumlimits_{d|n} sumlimits_{i=1}^{n/d} i[(i,n/d)=1]\ &= nsumlimits_{d|n} sumlimits_{i=1}^d i[(i,d)=1]\ &= nsumlimits_{d|n} sumlimits_{i=1}^{d} i sumlimits_{p|i,d} mu(p)\ &= nsumlimits_{d|n} sumlimits_{p|d} mu(p) imes psumlimits_{i=1}^{d/p}i\ &= nsumlimits_{p|n}mu(p) imes psumlimits_{d|n/p}sum(d) end{aligned} ]

    其中 (sum(i)=1+2+cdots+i)。时间复杂度 (O(nlogn))

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  • 原文地址:https://www.cnblogs.com/With-penguin/p/13694031.html
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