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  • Codeforces Round #270 A B C

    ADesign Tutorial: Learn from Math

    素数筛

    #include<bits/stdc++.h>
    using namespace std;
    const int N = 1e6 + 100;
    int a[N]={0};
    int main(){
    	int n;
    	cin >> n;
    	a[1] = 1;
    	for(int i = 2; i*i <= n; i++){
    		if(a[i] == 0){
    			for(int j = i*i; j <= n; j += i){
    				a[j] = 1;
    			}
    		}
    	}
    	
    	for(int i = 2; i <= n; i++){
    		if(a[i] && a[n-i]){
    			cout << i << " " << n - i <<"
    ";
    			return 0;
    		}
    	}
    	return 0;
    }
    

      BDesign Tutorial: Learn from Life

    贪心,从大到小,一次取k个,统计每次的楼层最高

    #include<bits/stdc++.h>
    using namespace std;
    const int N = 2e3;
    
    int n, k;
    int a[N];
    int main(){
    	cin >> n >> k;
    	for(int i = 0; i < n; i++){
    		cin >> a[i];
    	}
    	sort(a, a + n);
    	int sum = 0;
    	for(int i = n-1; i >= 0 ; i-=k){
    		sum += (a[i] - 1) * 2;
    	}
    	cout << sum << "
    ";
    	return 0;
    }
    

      CDesign Tutorial: Make It Nondeterministic

    模拟

    #include<bits/stdc++.h>
    using namespace std;
    const int N = 1e5 + 100;
    
    int n;
    char s1[N][60];
    char s2[N][60];
    int a[N];
    int main(){
    	cin >> n;
    	for(int i = 1; i <= n; i++){
    		cin >> s1[i] >> s2[i];
    	}
    	for(int i = 0; i < n; i++){
    		cin >> a[i];
    	}
    	int p=3;//可以选任意一个为handle
    	for(int i = 0; i < n-1; i++){
    		bool b1=strcmp(s1[a[i]], s1[a[i+1]]) == -1;
    		bool b2=strcmp(s2[a[i]], s1[a[i+1]]) == -1;
    		bool b3=strcmp(s1[a[i]], s2[a[i+1]]) == -1;
    		bool b4=strcmp(s2[a[i]], s2[a[i+1]]) == -1;
    		if(p==3){
    			if((b1|| b2) && (b3 || b4));
    			else if(b1 || b2)
    				p=1;//只能选第一个为handle
    			else if(b3 || b4)
    				p=2;//只能选第二个为handle
    			else{
    				cout<< "NO
    ";
    				return 0;
    			}
    		}
    		else if(p == 2){
    			if(b2 && b4)
    				p=3;
    			else if(b2)
    				p=1;
    			else if(b4)
    				p=2;
    			else{
    				cout<< "NO
    ";
    				return 0;
    			}
    		}
    		else if( p== 1){
    			if(b1 && b3)
    				p=3;
    			else if(b1)
    				p=1;
    			else if(b3)
    				p=2;
    			else{
    				cout<< "NO
    ";
    				return 0;
    			}
    		}
    	}
    	cout << "YES
    ";
    	return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/YJing814/p/11179983.html
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