zoukankan      html  css  js  c++  java
  • A Magic Lamp -- hdu -- 3183

    http://acm.hdu.edu.cn/showproblem.php?pid=3183

    A Magic Lamp

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 2515    Accepted Submission(s): 983


    Problem Description
    Kiki likes traveling. One day she finds a magic lamp, unfortunately the genie in the lamp is not so kind. Kiki must answer a question, and then the genie will realize one of her dreams. 
    The question is: give you an integer, you are allowed to delete exactly m digits. The left digits will form a new integer. You should make it minimum.
    You are not allowed to change the order of the digits. Now can you help Kiki to realize her dream?
     
    Input
    There are several test cases.
    Each test case will contain an integer you are given (which may at most contains 1000 digits.) and the integer m (if the integer contains n digits, m will not bigger then n). The given integer will not contain leading zero.
     
    Output
    For each case, output the minimum result you can get in one line.
    If the result contains leading zero, ignore it. 
     
    Sample Input
    178543 4
    1000001 1
    100001 2
    12345 2
    54321 2
     
    Sample Output
    13
    1
    0
    123
    321
     
    Source
    #include<iostream>
    #include<string.h>
    #include<stdio.h>
    #include<string.h>
    #include<stdlib.h>
    #include<algorithm>
    #include<queue>
    using namespace std;
    
    #define N 110000
    #define MOD 100000007
    
    char s[N];
    int a[N], m;
    
    int Find(int k);
    
    void Print();
    
    void Slove(int k);
    
    int main()
    {
        int n;
    
        while(scanf("%s%d", s, &n)!=EOF)
        {
            int i, j;
    
            m=n;
    
            memset(a, 0, sizeof(a));
            for(i=0; s[i]; i++)
                a[i] = s[i]-'0';
    
            i=0;
            while(1)
            {
                int next = Find(i);
                if(next==0 || next-i>m)
                    break;
    
                for(j=i; j<next; j++)
                {
                    a[j] = -1;
                    m--;
                }
    
    
                i = next;
                while(a[i]==0) i++;
            }
    
            Slove(i);
    
            Print();
        }
        return 0;
    }
    
    void Slove(int k)
    {
        int i, j, index, len=strlen(s)-1;
    
        while(1)
        {
            if(m==0) break;
    
            index=-1;
            for(i=k; i<=len; i++)
            {
                if(a[i]==-1) continue;
                j = i+1;
                while(a[j]==-1) j++;
    
                if(a[i]>a[j])
                {
                    index = i;
                    break;
                }
            }
            if(index==-1)
                break;
    
            a[index] = -1;
            m--;
        }
    }
    
    int Find(int k)
    {
        int i;
    
        for(i=k+1; s[i]; i++)
        {
            if(a[i]==0)
                return i;
        }
        return 0;
    }
    
    void Print()
    {
        int i, j, flag=0;
    
        for(i=0; s[i]; i++)
        {
            if(a[i]!=0 && a[i]!=-1)
                break;
        }
        for(j=i; s[j]; j++)
        {
            if(a[j]!=-1)
            {
                 printf("%d", a[j]);
                 flag = 1;
            }
        }
        if(!flag) printf("0");
    
        printf("
    ");
    }
    勿忘初心
  • 相关阅读:
    Sql 复习(1)
    记录一次git issue
    JWT自校验框架
    分布式事务分布式锁的常用解决方式
    SpringBoot开发文档
    SpringCloud的使用以及五大核心组件
    SpringMVC
    关于开发中使用AOP的坑
    SpringCloud使用feign远程调用服务注入映射接口失败问题
    springBoot使用Restful跳转路径回显异常问题
  • 原文地址:https://www.cnblogs.com/YY56/p/4965013.html
Copyright © 2011-2022 走看看