zoukankan      html  css  js  c++  java
  • Sliding Window

    Description

    An array of size n ≤ 106 is given to you. There is a sliding window of size k which is moving from the very left of the array to the very right. You can only see the k numbers in the window. Each time the sliding window moves rightwards by one position. Following is an example:
    The array is [1 3 -1 -3 5 3 6 7], and k is 3.
    在这里插入图片描述

    Your task is to determine the maximum and minimum values in the sliding window at each position.

    Input

    The input consists of two lines. The first line contains two integers n and k which are the lengths of the array and the sliding window. There are n integers in the second line.
    Output

    There are two lines in the output. The first line gives the minimum values in the window at each position, from left to right, respectively. The second line gives the maximum values.

    Sample Input
    8 3
    1 3 -1 -3 5 3 6 7

    Sample Output
    -1 -3 -3 -3 3 3
    3 3 5 5 6 7

    .
    .
    .
    .
    .
    分析
    单调队列即可
    注意m=1的情况

    .
    .
    .
    .
    .
    程序:

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    using namespace std;
    
    int a[1000010],q[1000010],n,m,p[1000010];
    
    void zx()
    {
    	int head=1,tail=1;
    	q[head]=1;
    	if (m==1) printf("%d ",a[q[head]]);
    	for (int i=2;i<=n;i++)
    	{
    		while (head<=tail&&a[q[tail]]>=a[i]) tail--;
    		tail++;
    		q[tail]=i;
    		while (i-q[head]+1>m) head++;
    		if (i>=m) printf("%d ",a[q[head]]);
    	}
    }
    
    void zd()
    {
    	int head=1,tail=1;
    	p[head]=1;
    	if (m==1) printf("%d ",a[p[head]]);
    	for (int i=2;i<=n;i++)
    	{
    		while (head<=tail&&a[p[tail]]<=a[i]) tail--;
    		tail++;
    		p[tail]=i;
    		while (i-p[head]+1>m) head++;
    		if (i>=m) printf("%d ",a[p[head]]);
    	}
    }
    
    int main()
    {
    	scanf("%d%d",&n,&m);
    	for (int i=1;i<=n;i++)
    		scanf("%d",&a[i]);
    	zx();
    	cout<<endl;
    	zd();
    	return 0;
    }
    
  • 相关阅读:
    用CSS3实现上下左右箭头
    让input框只能输入数字
    给内联元素设置宽高的几种方式
    当文本溢出包含的元素时加省略号之text-overflow
    通过box盒子模型给元素内容设置居中
    CSS3中的字体rem
    封装一个取消事件冒泡的方法
    HTML5 web workes实现多线程
    通过imeMode禁用键盘只能输入数字
    jquery的children方法和css3选择器配合使用
  • 原文地址:https://www.cnblogs.com/YYC-0304/p/10292788.html
Copyright © 2011-2022 走看看