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  • C#中两个List<TModel>中根据指定条件--判断并获取不同数据的数据集合

    C#中两个List<TModel>中根据指定条件--判断并获取不同数据的数据集合

    原始需求:已经插入的数据不再重复插入(所有数据中排除已有数据,不存在数据以新对象形式存储在对象三种)

    方式一:

     public class Test
        {
            public int age { get; set; }
            public string name { get; set; }
            public int score { get; set; }
        }
                List<Test> list1 = new List<Test>();
                list1.Add(new Test { score = 10, name = "001" });
                list1.Add(new Test { score = 20, name = "002" });
                list1.Add(new Test { score = 30, name = "003" });
                list1.Add(new Test { score = 40, name = "004" });
                list1.Add(new Test { score = 50, name = "005" });
                list1.Add(new Test { score = 60, name = "005" });
    
                List<Test> list2 = new List<Test>();
                list2.Add(new Test { score = 10, name = "001" });
                list2.Add(new Test { score = 20, name = "002" });
                list2.Add(new Test { score = 30, name = "003" });
                list2.Add(new Test { score = 40, name = "004" });
    
                //list3 return 2
                List<Test> list3 = list1.Where(x => !list2.Any(x2 => x.score == x2.score)).ToList();
                //list4 return 2
                List<Test> list4 = list1.Where(x => list2.All(x2 => x.score != x2.score)).ToList();
    
                MessageBox.Show("list3==" + list3.Count+"
    list4==" + list4.Count);     
    

    方式二:list1、list2数据参考方式一

    public class DifferentModel : IEqualityComparer<Test>
        {
            public bool Equals(Test x, Test y)
            {
                return x.score == y.score;
            }
    
            public int GetHashCode(Test obj)
            {
                return obj.ToString().GetHashCode();
            }
        }
    
    List<Test> different = list1.Except(list2, new DifferentModel()).ToList();//差集
    
    MessageBox.Show("different=="+different.Count);
    

    方式三:仅供参考,根据实际情况注意Contains关键字 注意使用——不建议使用

    //return 2

    List<Test> temp = list1.Where(p => !list2.Select(b => b.score).Contains(p.score)).ToList();
    MessageBox.Show("temp=="+temp.Count);

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  • 原文地址:https://www.cnblogs.com/YYkun/p/11639802.html
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