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  • Codeforces Round #483 (Div. 2) C.Finite or not? 关于欧几里得的应用

    C. Finite or not?

    Input

    The first line contains a single integer nn (1n10^) — the number of queries.

    Next nn lines contain queries, one per line. Each line contains three integers pq and b (0p10^181q10^18 2b10^18). All numbers are given in notation with base 10.

    Output

    For each question, in a separate line, print Finite if the fraction is finite and Infinite otherwise.

    input
    2
    6 12 10
    4 3 10
    output
    Finite
    Infinite

    即要求输入,p,q,b.

    问:是否有n个p/q能组成b,n必需为有理数,可以是小数,但必需有限。

    思路:该问题立刻就想到gcd,主要是与b的关系,应有b与q的gcd关系,进行求解。

     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 typedef unsigned long long unsll;
     4 
     5 int n;
     6 unsll p,q,b;
     7 unsll gcd(int a,int b)
     8 {
     9     return b==0? a:gcd(b,a%b);
    10 }
    11 
    12 int main()
    13 {
    14     ios_base::sync_with_stdio(0); cin.tie(0);
    15 
    16     while( cin >> n ){
    17         while(n--){
    18             cin >> p >> q >> b;
    19             if(p%q==0){
    20                 puts("Finite");
    21                 continue;
    22             }
    23 
    24             unsll cheek=gcd(p,q);
    25             q/=cheek;
    26             cheek=gcd(b,q);
    27             while(q!=1&&cheek!=1){
    28                 while(q%cheek==0) q/=cheek;
    29                 cheek=gcd(b,q);
    30             }
    31             if(q==1)
    32                 puts("Finite");
    33             else puts("Infinite");
    34         }
    35     }
    36     return 0;
    37 }
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  • 原文地址:https://www.cnblogs.com/ZQUACM-875180305/p/9046411.html
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