动态树LCT模板题
#include<cstdio>
#include<cctype>
#include<algorithm>
using namespace std;
inline int read()
{
int x = 0, flag = 1;
char c;
while(! isgraph(c = getchar()))
if(c == '-')
flag *= - 1;
while(isgraph(c))
x = x * 10 + c - '0', c = getchar();
return x * flag;
}
inline void println(int x)
{
if(x < 0)
putchar('-');
if(x == 0)
putchar('0');
int top = 0, ans[10 + (1 << 4)];
while(x)
ans[top ++] = x % 10, x /= 10;
for(; top; top --)
putchar(ans[top - 1] + '0');
putchar('
');
}
const int MAXN = (int)2e5 + (1 << 5);
struct node
{
int isroot, ch[2], fa, size;
}T[MAXN];
void update(int u)
{
T[u].size = ((T[u].ch[0] == - 1) ? 0 : T[T[u].ch[0]].size)
+ ((T[u].ch[1] == - 1) ? 0 : T[T[u].ch[1]].size) + 1;
}
inline int get_rela(int u)
{
return u == T[T[u].fa].ch[1];
}
void rotate(int u)
{
int fa = T[u].fa, fafa = T[T[u].fa].fa, rela = get_rela(u);
T[T[u].ch[rela ^ 1]].fa = fa;
T[fa].ch[rela] = T[u].ch[rela ^ 1];
T[u].ch[rela ^ 1] = fa;
T[fa].fa = u;
T[u].fa = fafa;
if(T[fa].isroot)
T[fa].isroot = 0, T[u].isroot = 1;
else
T[fafa].ch[T[fafa].ch[1] == fa] = u;
update(fa), update(u);
}
void splay(int u)
{
while(1)
{
if(T[u].isroot)
break;
if(! T[T[u].fa].isroot)
rotate((get_rela(u) == get_rela(T[u].fa)) ? T[u].fa : u);
rotate(u);
}
}
void access(int u)
{
splay(u);
while(T[u].fa != - 1)
{
int fa = T[u].fa;
splay(fa);
if(T[fa].ch[1] != - 1)
T[T[fa].ch[1]].isroot = 1;
T[u].isroot = 0;
T[fa].ch[1] = u;
update(fa);
splay(u);
}
}
int main()
{
#ifndef ONLINE_JUDGE
freopen("BZOJ2002.in", "r", stdin);
freopen("BZOJ2002.out", "w", stdout);
#endif
int n = read();
T[n].fa = - 1;
for(int i = 0; i < n; i ++)
T[i].fa = min(read() + i, n);
for(int i = 0; i <= n; i ++)
T[i].size = 1, T[i].isroot = 1, T[i].ch[0] = T[i].ch[1] = - 1;
int m = read();
for(int i = 0; i < m; i ++)
{
int opt = read();
if(opt == 1)
{
int u = read();
access(u);
println(T[T[u].ch[0]].size); //这里要稍微注意一下
continue;
}
int u = read();
splay(u);
T[T[u].ch[0]].fa = T[u].fa;
T[T[u].ch[0]].isroot = 1;
T[u].ch[0] = - 1;
T[u].size = ((T[u].ch[1] == - 1) ? 0 : T[T[u].ch[1]].size) + 1;
T[u].fa = min(n, read() + u);
}
}