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  • BestCoder Round #3(A)

    题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=4907

    解题思路:

      二分或简单模拟。

    代码:二分

     1 #include <algorithm>
     2 #include <iostream>
     3 #include <sstream>
     4 #include <cstdlib>
     5 #include <cstring>
     6 #include <cstdio>
     7 #include <string>
     8 #include <bitset>
     9 #include <vector>
    10 #include <queue>
    11 #include <stack>
    12 #include <cmath>
    13 #include <list>
    14 //#include <map>
    15 #include <set>
    16 using namespace std;
    17 /***************************************/
    18 #define ll long long
    19 #define int64 __int64
    20 #define PI 3.1415927
    21 /***************************************/
    22 const int INF = 0x7f7f7f7f;
    23 const double eps = 1e-8;
    24 const double PIE=acos(-1.0);
    25 const int d1x[]= {0,-1,0,1};
    26 const int d1y[]= {-1,0,1,0};
    27 const int d2x[]= {0,-1,0,1};
    28 const int d2y[]= {1,0,-1,0};
    29 const int fx[]= {-1,-1,-1,0,0,1,1,1};
    30 const int fy[]= {-1,0,1,-1,1,-1,0,1};
    31 const int dirx[]= {-1,1,-2,2,-2,2,-1,1};
    32 const int diry[]= {-2,-2,-1,-1,1,1,2,2};
    33 /*vector <int>map[N];map[a].push_back(b);int len=map[v].size();*/
    34 /***************************************/
    35 void openfile()
    36 {
    37     freopen("data.in","rb",stdin);
    38     freopen("data.out","wb",stdout);
    39 }
    40 priority_queue<int> qi1;
    41 priority_queue<int, vector<int>, greater<int> >qi2;
    42 /**********************华丽丽的分割线,以上为模板部分*****************/
    43 const int M=100005;
    44 int a[2*M],b[2*M];
    45 int find(int v,int n)
    46 {
    47     int sta=0,end=n,mid;
    48     while(sta+1!=end)
    49     {
    50         mid=sta+(end-sta)/2;
    51         if (b[mid]<v)
    52             sta=mid;
    53         else
    54             end=mid;
    55     }
    56     if(v>=b[end])
    57         return v;
    58     else if (v<=b[sta])
    59         return b[sta];
    60     else
    61         return b[end];
    62 
    63 }
    64 int main()
    65 {
    66     int cas;
    67     scanf("%d",&cas);
    68     while(cas--)
    69     {
    70         int n,q;
    71         scanf("%d",&n);
    72         scanf("%d",&q);
    73         int x;
    74         memset(a,0,sizeof(a));
    75         memset(b,0,sizeof(b));
    76         for(int i=0;i<n;i++)
    77         {
    78              scanf("%d",&x);
    79              a[x]=1;
    80         }
    81         int d=-1;
    82         for(int i=1;i<2*M;i++)
    83         {
    84             if (a[i]==0)
    85             {
    86                  b[++d]=i;
    87             }
    88         }
    89         while(q--)
    90         {
    91             scanf("%d",&x);
    92             printf("%d
    ",find(x,d));
    93         }
    94     }
    95     return 0;
    96 }
    View Code

    代码:模拟

        

     1 #include <algorithm>
     2 #include <iostream>
     3 #include <sstream>
     4 #include <cstdlib>
     5 #include <cstring>
     6 #include <cstdio>
     7 #include <string>
     8 #include <bitset>
     9 #include <vector>
    10 #include <queue>
    11 #include <stack>
    12 #include <cmath>
    13 #include <list>
    14 //#include <map>
    15 #include <set>
    16 using namespace std;
    17 /***************************************/
    18 #define ll long long
    19 #define int64 __int64
    20 #define PI 3.1415927
    21 /***************************************/
    22 const int INF = 0x7f7f7f7f;
    23 const double eps = 1e-8;
    24 const double PIE=acos(-1.0);
    25 const int d1x[]= {0,-1,0,1};
    26 const int d1y[]= {-1,0,1,0};
    27 const int d2x[]= {0,-1,0,1};
    28 const int d2y[]= {1,0,-1,0};
    29 const int fx[]= {-1,-1,-1,0,0,1,1,1};
    30 const int fy[]= {-1,0,1,-1,1,-1,0,1};
    31 const int dirx[]= {-1,1,-2,2,-2,2,-1,1};
    32 const int diry[]= {-2,-2,-1,-1,1,1,2,2};
    33 /*vector <int>map[N];map[a].push_back(b);int len=map[v].size();*/
    34 /***************************************/
    35 void openfile()
    36 {
    37     freopen("data.in","rb",stdin);
    38     freopen("data.out","wb",stdout);
    39 }
    40 priority_queue<int> qi1;
    41 priority_queue<int, vector<int>, greater<int> >qi2;
    42 /**********************华丽丽的分割线,以上为模板部分*****************/
    43 const int M=100005;
    44 int a[2*M],b[2*M];
    45 int main()
    46 {
    47     int cas;
    48     scanf("%d",&cas);
    49     while(cas--)
    50     {
    51         int n,q;
    52         scanf("%d",&n);
    53         scanf("%d",&q);
    54         int x;
    55         memset(a,0,sizeof(a));
    56         memset(b,0,sizeof(b));
    57         for(int i=0;i<n;i++)
    58         {
    59              scanf("%d",&x);
    60              a[x]=1;
    61         }
    62         int k=1;
    63         for(int i=2*M;i>0;i--)
    64         {
    65             if (a[i]==1)
    66             {
    67                 b[i]=b[i+1];
    68                 continue;
    69             }
    70             b[i]=i;
    71         }
    72         while(q--)
    73         {
    74             scanf("%d",&x);
    75             printf("%d
    ",b[x]);
    76         }
    77     }
    78     return 0;
    79 }
    View Code
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  • 原文地址:https://www.cnblogs.com/ZhaoPengkinghold/p/3889382.html
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