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  • Big Number(大数)

    Big Number

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 5857    Accepted Submission(s): 4093
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    Problem Description
    As we know, Big Number is always troublesome. But it's really important in our ACM. And today, your task is to write a program to calculate A mod B.

    To make the problem easier, I promise that B will be smaller than 100000.

    Is it too hard? No, I work it out in 10 minutes, and my program contains less than 25 lines.
     
    Input
    The input contains several test cases. Each test case consists of two positive integers A and B. The length of A will not exceed 1000, and B will be smaller than 100000. Process to the end of file.
     
    Output
    For each test case, you have to ouput the result of A mod B.
     
    Sample Input
    2 3
    12 7
    152455856554521 3250
     
    Sample Output
    2
    5
    1521
     1 #include <iostream>
     2 #include <cstring>
     3 using namespace std;
     4 int main()
     5 {
     6     int n,i,j;
     7     char a[1002];
     8     while(cin>>a>>n)
     9     {
    10         int count=0,c=0,m=0;
    11         count=strlen(a)-1;
    12         for(i=0;i<=count;i++)
    13         {
    14             m=a[i]-'0'+c*10;
    15             c=m%n;
    16         }
    17         cout<<c<<endl;
    18         memset(a,0,sizeof(a));
    19     }
    20 }
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  • 原文地址:https://www.cnblogs.com/a1225234/p/4602731.html
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