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  • Java实现LeetCode_0013_RomanToInteger

    package javaLeetCode.primary;
    
    import java.util.HashMap;
    import java.util.Map;
    import java.util.Scanner;
    import java.util.Stack;
    
    public class RomanToInteger_13 {
    	public static void main(String[] args) {
    		System.out.println("Please input a roman numeral:");
    		@SuppressWarnings("resource")
    		Scanner input = new Scanner(System.in);
    		String s = input.next();
    		System.out.println(romanToInt_3(s));
    	}// end main()
    
    	/**
    	 * Conventional thinking.
    	 * Scan from head to tail and use Map or Array.
    	 */
    	/*
    	 * Test Data: 
    	 * III--3 
    	 * IV--4 
    	 * IX--9 
    	 * LVIII--58 
    	 * MCMXCIV--1994
    	 * MCCCXIV--1314
    	 * MMMIX--3009
    	 * MMMCCXLIX--3249
    	 */
    	public static int romanToInt_1(String s) {
    		char[] str = s.toCharArray();
    		Map<Character, Integer> map = new HashMap<Character, Integer>();
    		map.put('I', 1);
    		map.put('V', 5);
    		map.put('X', 10);
    		map.put('L', 50);
    		map.put('C', 100);
    		map.put('D', 500);
    		map.put('M', 1000);
    
    		int num = 0;
    		for (int i = 0; i < s.length() - 1; i++) {
    			if (map.get(str[i]) >= map.get(str[i + 1])) {
    				num += map.get(str[i]);
    			} else {
    				num -= map.get(str[i]);
    			} // end if
    		} // end for
    		num += map.get(str[str.length - 1]);
    		return num;
    	}// end romanToInt()
    	
    	/**
    	 * Conventional thinking.
    	 * Scan from head to tail and use Stack to reserve the total.
    	 */
    	public static int romanToInt_2(String s) {
    		char[] str = s.toCharArray();
    		Stack <Integer>romanStack = new Stack<Integer>();
    		Map<Character, Integer> map = new HashMap<Character, Integer>();
    		map.put('I', 1);
    		map.put('V', 5);
    		map.put('X', 10);
    		map.put('L', 50);
    		map.put('C', 100);
    		map.put('D', 500);
    		map.put('M', 1000);
    		
    
    		int num = 0;
    		romanStack.push(map.get(str[0]));
    		for (int i = 1; i < s.length() ; i++) {
    			if (map.get(str[i]) <= map.get(str[i - 1])) {
    				romanStack.push(map.get(str[i]));
    			} else {
    				romanStack.push(map.get(str[i])-romanStack.pop());
    			} // end if
    		} // end for
    		
    		//Don't write "for(int I =0;I < romanStack. The size ();I++) ", 
    		//because the stack size is fetched every time the loop occurs
    		int length = romanStack.size();
    		for(int i=0;i<length;i++) {
    			num += romanStack.pop();
    		}//end for
    		return num;
    	}// end romanToInt()
    	
    	public static int romanToInt_3(String s) {
    		int num = 0;
    		for(int i=0;i<s.length();i++) {
    			char c = s.charAt(i);
    			if(c=='I') {num += 1;}
    			if(c=='V') {num += 5;}
    			if(c=='X') {num += 10;}
    			if(c=='L') {num += 50;}
    			if(c=='C') {num += 100;}
    			if(c=='D') {num += 500;}
    			if(c=='M') {num += 1000;}
    			
    		}//end for
    		
    		if(s.contains("IV")) {num -= 2;}
    		if(s.contains("IX")) {num -= 2;}
    		if(s.contains("XL")) {num -= 20;}
    		if(s.contains("XC")) {num -= 20;}
    		if(s.contains("CD")) {num -= 200;}
    		if(s.contains("CM")) {num -= 200;}
    		
    		return num;
    	}// end romanToInt()
    }// end RomanToInteger_13
    
    
    
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  • 原文地址:https://www.cnblogs.com/a1439775520/p/13076601.html
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