找零问题:假设商店老板需要找零n元钱,钱币的面额有:100元、50元、20元、5元、1元,如何找零使得所需钱币的数量最少?
# greedy algorithm
money = [100,50,20,5,1]
def change_money(x):
change = [0,0,0,0,0]
for i,m in enumerate(money):
change[i] = x // money[i]
x = x % money[i]
if x > 0:
print("还剩%s" % x)
return change
print(change_money(356.2))