- 题目描述:
-
给出年分m和一年中的第n天,算出第n天是几月几号。
- 输入:
-
输入包括两个整数y(1<=y<=3000),n(1<=n<=366)。
- 输出:
-
可能有多组测试数据,对于每组数据,
按 yyyy-mm-dd的格式将输入中对应的日期打印出来。
- 样例输入:
-
2000 3 2000 31 2000 40 2000 60 2000 61 2001 60
- 样例输出:
-
2000-01-03 2000-01-31 2000-02-09 2000-02-29 2000-03-01 2001-03-01
1 #include <stdio.h> 2 bool isRun(int x) 3 { 4 return (x%4==0&&x%100!=0)||x%400==0; 5 } 6 int main() 7 { 8 int i,y,n; 9 int month[]={0,31,28,31,30,31,30,31,31,30,31,30,31}; 10 // freopen("in.txt","r",stdin); 11 while(scanf("%d %d",&y,&n)!=EOF) 12 { 13 i=1; 14 month[2]=28; 15 if (isRun(y)) 16 month[2]++; 17 while (n>month[i]) 18 { 19 n-=month[i]; 20 i++; 21 } 22 printf("%04d-%02d-%02d\n",y,i,n); 23 } 24 return 0; 25 }
注意格式 输出格式yyyy-mm-dd 四位数-二位数-二位数
/* printf example */ #include <stdio.h> int main() { printf ("Characters: %c %c \n", 'a', 65); printf ("Decimals: %d %ld\n", 1977, 650000L); printf ("Preceding with blanks: %10d \n", 1977); printf ("Preceding with zeros: %010d \n", 1977); printf ("Some different radixes: %d %x %o %#x %#o \n", 100, 100, 100, 100, 100); printf ("floats: %4.2f %+.0e %E \n", 3.1416, 3.1416, 3.1416); printf ("Width trick: %*d \n", 5, 10); printf ("%s \n", "A string"); return 0; }
Output:
Characters: a A Decimals: 1977 650000 Preceding with blanks: 1977 Preceding with zeros: 0000001977 Some different radixes: 100 64 144 0x64 0144 floats: 3.14 +3e+000 3.141600E+000 Width trick: 10 A string