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  • [leetcode] 73. 矩阵置零

    73. 矩阵置零

    这次直接上代码吧

    class Solution {
        public void setZeroes(int[][] matrix) {
            int m = matrix.length;
            if (m == 0) {
                return;
            }
            int n = matrix[0].length;
            for (int i = 0; i < m; i++) {
                for (int j = 0; j < n; j++) {
                    if (matrix[i][j] == 0) {
                        matrix[i][j] = -1;
                        for (int k = 0; k < m; k++) {
                            if (matrix[k][j] != 0) matrix[k][j] = Integer.MIN_VALUE / 2;
                        }
                        for (int k = 0; k < n; k++) {
                            if (matrix[i][k] != 0) matrix[i][k] = Integer.MIN_VALUE / 2;
                        }
                    }
                }
            }
            for (int i = 0; i < m; i++) {
                for (int j = 0; j < n; j++) {
                    if (matrix[i][j] == Integer.MIN_VALUE / 2) {
                        matrix[i][j] = 0;
                    }
                }
            }
        }
    }
    

    其实我做的不严谨,正确做法应该是先统计出来0出现的位置,然后再进行操作。但是我懒得改了

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  • 原文地址:https://www.cnblogs.com/acbingo/p/9369329.html
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