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  • 作业32

    作业32

    数据在作业31

    1、查询所有的课程的名称以及对应的任课老师姓名

    SELECT cname,tname FROM course INNER JOIN teacher ON course.teacher_id=teacher.tid ;
    

    2、查询学生表中男女生各有多少人

    SELECT gender,COUNT(sid) FROM student GROUP BY gender;
    

    3、查询物理成绩等于100的学生的姓名

    SELECT sname FROM student WHERE sid in (SELECT student_id FROM score WHERE course_id in (SELECT cid FROM course WHERE cname='物理') and num = 100);
    

    4、查询平均成绩大于八十分的同学的姓名和平均成绩

    SELECT student.sname,t1.avg_num FROM student INNER JOIN (SELECT student_id,AVG(num) as avg_num FROM score GROUP BY student_id HAVING AVG(num)>80) AS t1 ON  student.sid = t1.student_id;
    

    5、查询所有学生的学号,姓名,选课数,总成绩

    SELECT t1.student_id as '学号',student.sname as '名字',t1.score as '总成绩',t1.num as '选课数'  FROM student INNER JOIN (SELECT student_id,SUM(num) as score,COUNT(course_id) as num FROM score GROUP BY student_id) as t1 on student.sid = t1.student_id;
    

    6、 查询姓李老师的个数

    SELECT COUNT(tid) FROM teacher WHERE teacher.tname LIKE '李%';
    

    7、 查询没有报李平老师课的学生姓名

    SELECT * FROM student WHERE sid not in (SELECT DISTINCT score.student_id FROM score WHERE course_id in (SELECT cid FROM course WHERE teacher_id in (SELECT tid FROM teacher WHERE tname = '李平老师')));
    

    8、 查询物理课程比生物课程高的学生的学号

    SELECT
    	id1 
    FROM
    	( SELECT student_id AS id1, score.num AS phy_score FROM score WHERE course_id = ( SELECT cid FROM course WHERE cname = '物理' ) ) AS t1
    	INNER JOIN ( SELECT student_id AS id2, score.num AS bio_score FROM score WHERE course_id = ( SELECT cid FROM course WHERE cname = '生物' ) ) AS t2 ON t1.id1 = t2.id2 
    WHERE
    	phy_score > bio_score;
    

    9、 查询没有同时选修物理课程和体育课程,只选了其中一门的学生姓名

    SELECT student.sname FROM student INNER JOIN (SELECT student_id FROM score WHERE course_id IN (SELECT cid FROM course WHERE course.cname in ('体育','物理')) GROUP BY student_id HAVING COUNT(course_id)=1) as t1 on student.sid = t1.student_id;
    
    

    10、查询挂科超过两门(包括两门)的学生姓名和班级

    SELECT student.sname,class.caption FROM student INNER JOIN class on student.class_id = class.cid WHERE sid in (SELECT student_id FROM score WHERE num<60 GROUP BY student_id HAVING COUNT(course_id)>=2);
    
    

    11、查询选修了所有课程的学生姓名

    SELECT sname FROM student WHERE sid IN (SELECT student_id FROM score GROUP BY student_id HAVING COUNT(course_id) = (SELECT COUNT(cid) FROM course));
    

    12、查询李平老师教的课程的所有成绩记录

    SELECT student.sname,t1.course_ID,t1.num FROM student INNER JOIN (SELECT * FROM score WHERE course_id in (SELECT cid FROM course WHERE teacher_id in (SELECT tid FROM teacher WHERE tname = '李平老师'))) AS t1 ON student.sid = t1.student_id;
    

    13、查询全部学生都选修了的课程号和课程名

    SELECT
    	course.cid,
    	cname 
    FROM
    	course 
    WHERE
    	cid IN ( SELECT course_id FROM score GROUP BY course_id HAVING COUNT( sid ) = ( SELECT COUNT( student.sid ) FROM student ) );
    

    14、查询每门课程被选修的次数

    SELECT course_id,COUNT(sid) FROM score GROUP BY course_id;
    

    15、查询只选修了一门课程的学生姓名和学号

    SELECT sid,sname FROM student WHERE sid in (SELECT student_id FROM score GROUP BY student_id HAVING COUNT(sid) = 1);
    

    16、查询所有学生考出的成绩并按从高到低排序(成绩去重)

    SELECT DISTINCT num FROM score ORDER BY num DESC;
    

    17、查询平均成绩大于85的学生姓名和平均成绩

    SELECT sname,avg_num FROM student INNER JOIN (SELECT student_id,AVG(num) as avg_num FROM score GROUP BY student_id HAVING AVG(num)>85) AS t1 on student.sid = t1.student_id;
    

    18、查询生物成绩不及格的学生姓名和对应生物分数

    SELECT student.sname,t1.num FROM student INNER JOIN (SELECT student_id,num FROM score WHERE course_id = (SELECT cid FROM course WHERE cname = '生物') and num<60) as t1 on student.sid = t1.student_id;
    
    SELECT
        sname 姓名,
        num 生物成绩
    FROM
        score
    LEFT JOIN course ON score.course_id = course.cid
    LEFT JOIN student ON score.student_id = student.sid
    WHERE
        course.cname = '生物'
    AND score.num < 60;
    

    19、查询在所有选修了李平老师课程的学生中,这些课程(李平老师的课程,不是所有课程)平均成绩最高的学生姓

    SELECT sname FROM student WHERE sid = (SELECT student_id FROM score WHERE course_id in (SELECT cid FROM course WHERE teacher_id in (SELECT tid FROM teacher WHERE tname = '李平老师')) GROUP BY student_id ORDER BY AVG(num) DESC LIMIT 1);
    
    

    20、查询每门课程成绩最好的前两名学生姓名

    # 得到学生id
    SELECT
    	* 
    FROM
    	score
    	INNER JOIN (
    	SELECT
    		t1.course_id AS course_id,
    		t1.f_num AS f_num,
    		t2.s_num AS s_num 
    	FROM
    		(
    		SELECT
    			score.course_id AS course_id,
    			max( num ) AS s_num 
    		FROM
    			score
    			INNER JOIN ( SELECT course_id, max( num ) AS f_num FROM score GROUP BY course_id ) AS t ON score.course_id = t.course_id 
    		WHERE
    			score.num < t.f_num 
    		GROUP BY
    			course_id 
    		) AS t2
    		INNER JOIN ( SELECT course_id, max( num ) AS f_num FROM score GROUP BY course_id ) AS t1 ON t2.course_id = t1.course_id 
    	) AS t3 ON score.course_id = t3.course_id 
    WHERE num BETWEEN t3.s_num and t3.f_num
    
    # 所有前两名的学生姓名
    SELECT
    	sname 
    FROM
    	student 
    WHERE
    	sid IN (
    	SELECT
    		student_id 
    	FROM
    		score
    		INNER JOIN (
    		SELECT
    			t1.course_id AS course_id,
    			t1.f_num AS f_num,
    			t2.s_num AS s_num 
    		FROM
    			(
    			SELECT
    				score.course_id AS course_id,
    				max( num ) AS s_num 
    			FROM
    				score
    				INNER JOIN ( SELECT course_id, max( num ) AS f_num FROM score GROUP BY course_id ) AS t ON score.course_id = t.course_id 
    			WHERE
    				score.num < t.f_num 
    			GROUP BY
    				course_id 
    			) AS t2
    			INNER JOIN ( SELECT course_id, max( num ) AS f_num FROM score GROUP BY course_id ) AS t1 ON t2.course_id = t1.course_id 
    		) AS t3 ON score.course_id = t3.course_id 
    	WHERE
    		num BETWEEN t3.s_num 
    	AND t3.f_num 
    	)
    

    21、查询不同课程但成绩相同的学号,课程号,成绩

    
    

    22、查询没学过“叶平”老师课程的学生姓名以及选修的课程名称;

    
    

    23、查询所有选修了学号为1的同学选修过的一门或者多门课程的同学学号和姓名;

    
    

    24、任课最多的老师中学生单科成绩最高的学生姓名

    
    
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  • 原文地址:https://www.cnblogs.com/achai222/p/12865292.html
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