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  • bzoj2049: [Sdoi2008]Cave 洞穴勘测 lct裸题

    题意:三种操作一种摧毁一条边,一种链接一条边,一种查询两个点是否联通
    题解:lct的link和cut即可

    /**************************************************************
        Problem: 2049
        User: walfy
        Language: C++
        Result: Accepted
        Time:1896 ms
        Memory:1508 kb
    ****************************************************************/
     
    //#pragma comment(linker, "/stack:200000000")
    //#pragma GCC optimize("Ofast,no-stack-protector")
    //#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
    //#pragma GCC optimize("unroll-loops")
    #include<bits/stdc++.h>
    #define fi first
    #define se second
    #define mp make_pair
    #define pb push_back
    #define pi acos(-1.0)
    #define ll long long
    #define vi vector<int>
    #define mod 1000000007
    #define ld long double
    #define C 0.5772156649
    #define ls l,m,rt<<1
    #define rs m+1,r,rt<<1|1
    #define pil pair<int,ll>
    #define pli pair<ll,int>
    #define pii pair<int,int>
    #define cd complex<double>
    #define ull unsigned long long
    #define base 1000000000000000000
    #define fio ios::sync_with_stdio(false);cin.tie(0)
     
    using namespace std;
     
    const double eps=1e-6;
    const int N=10000+1,maxn=5000+10,inf=0x3f3f3f3f,INF=0x3f3f3f3f3f3f3f3f;
     
    struct LCT{
        int fa[N],ch[N][2],rev[N],q[N];
        bool isroot(int x){return ch[fa[x]][0]!=x&&ch[fa[x]][1]!=x;}
        void pushup(int x){}
        void pushdown(int x)
        {
            if(rev[x])
            {
                rev[x]=0;swap(ch[x][0],ch[x][1]);
                rev[ch[x][0]]^=1,rev[ch[x][1]]^=1;
            }
        }
        void Rotate(int x)
        {
            int y=fa[x],z=fa[y],l,r;
            if(ch[y][0]==x)l=0,r=l^1;
            else l=1,r=l^1;
            if(!isroot(y))
            {
                if(ch[z][0]==y)ch[z][0]=x;
                else ch[z][1]=x;
            }
            fa[x]=z;fa[y]=x;fa[ch[x][r]]=y;
            ch[y][l]=ch[x][r];ch[x][r]=y;
            pushup(y);pushup(x);
        }
        void splay(int x)
        {
            int top=1;q[top]=x;
            for(int i=x;!isroot(i);i=fa[i])q[++top]=fa[i];
            for(int i=top;i;i--)pushdown(q[i]);
            while(!isroot(x))
            {
                int y=fa[x],z=fa[y];
                if(!isroot(y))
                {
                    if((ch[y][0]==x)^(ch[z][0]==y))Rotate(x);
                    else Rotate(y);
                }
                Rotate(x);
            }
        }
        void access(int x){for(int y=0;x;y=x,x=fa[x])splay(x),ch[x][1]=y,pushup(x);}
        void makeroot(int x){access(x),splay(x),rev[x]^=1;}
        int findroot(int x){access(x),splay(x);while(ch[x][0])x=ch[x][0];return x;}
        void split(int x,int y){makeroot(x),access(y),splay(y);}
        void cut(int x,int y){split(x,y);if(ch[y][0]==x)ch[y][0]=0,fa[x]=0;}
        void link(int x,int y){makeroot(x),fa[x]=y;}
    }lct;
    char s[N];
    int main()
    {
        int n,m;
        scanf("%d%d",&n,&m);
        while(m--)
        {
            char op[10];
            int x,y;
            scanf("%s%d%d",op,&x,&y);
            if(op[0]=='Q')
            {
                int fx=lct.findroot(x),fy=lct.findroot(y);
                if(fx!=fy)puts("No");
                else puts("Yes");
            }
            else if(op[0]=='C')
            {
                int fx=lct.findroot(x),fy=lct.findroot(y);
                if(fx!=fy)lct.link(x,y);
            }
            else if(op[0]=='D')
            {
                int fx=lct.findroot(x),fy=lct.findroot(y);
                if(fx==fy)lct.cut(x,y);
            }
        }
        return 0;
    }
    /********************
    200 5
    Query   123 127
    Connect 123 127
    Query   123 127
    Destroy 127 123
    Query   123 127
    ********************/
    
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  • 原文地址:https://www.cnblogs.com/acjiumeng/p/9108513.html
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