[SCOI2010]序列操作

题目链接：

一眼看过去就是ODT瞎搞，题解区一堆线段树巨长的emmm

#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define re register
#define pb push_back
#define fi first
const int N=1e6+10;
void read(int &a)
{
    a=0;int d=1;char ch;
    while(ch=getchar(),ch>'9'||ch<'0')
        if(ch=='-')
            d=-1;
    a=ch^48;
    while(ch=getchar(),ch>='0'&&ch<='9')
        a=(a<<3)+(a<<1)+(ch^48);
    a*=d;
}
struct note
{
    int l,r;
    mutable bool v;
    note(int L,int R=-1,int V=0){l=L,r=R,v=V;}
    bool operator < (const note &x) const
    {
        return l<x.l;
    }
};
set <note> s;
set <note> :: iterator split(int pos)
{
    auto it=s.lower_bound(note(pos));
    if(it!=s.end()&&it->l==pos) return it;
    it--;
    if(it->r<pos) return s.end();
    int L=it->l,R=it->r;
    bool V=it->v;
    s.erase(it);
    s.insert(note(L,pos-1,V));
    return s.insert(note(pos,R,V)).fi;
}
void ass(int l,int r,int val)
{
    auto it2=split(r+1),it1=split(l);
    s.erase(it1,it2);
    s.insert(note(l,r,val));
}
void rev(int l,int r)
{
    auto it2=split(r+1),it1=split(l);
    for(;it1!=it2;it1++) it1->v^=1;
}
int query1(int l,int r)
{
    int ans=0;
    auto it2=split(r+1),it1=split(l);
    for(;it1!=it2;it1++) ans+=it1->v?it1->r-it1->l+1:0;
    return ans;
}
int query2(int l,int r)
{
    int ans=0,sum=0;
    auto it2=split(r+1),it1=split(l);
    for(;it1!=it2;it1++)
    {
        if(it1->v==0) ans=max(ans,sum),sum=0;
        else sum+=it1->r-it1->l+1;
    }
    ans=max(ans,sum);
    return ans;
}
int main()
{
    int n,m;
    read(n),read(m);
    for(re int i=0,x;i<n;i++) read(x),s.insert(note(i,i,x));
    s.insert(note(n,n,0));
    for(re int i=1,op,a,b;i<=m;i++)
    {
        read(op),read(a),read(b);
        if(op==0) ass(a,b,0);
        else if(op==1) ass(a,b,1);
        else if(op==2) rev(a,b);
        else if(op==3) printf("%d
",query1(a,b));
        else printf("%d
",query2(a,b));
    }
    return 0;
}