a letter and a number

题目217
a letter and a number
时间限制：3000 ms | 内存限制：65535 KB
难度：1
描述
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).
输入
On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).
输出
for each case, you should the result of y+f(x) on a line
样例输入
6
R 1
P 2
G 3
r 1
p 2
g 3样例输出
19
18
10
-17
-14

#include<stdio.h>



 int main(){
     int T;
      scanf("%d",&T);
        while(T--){
            int y;
             char x;
         getchar();  //过滤空格 
        scanf("%c %d",&x,&y);
        
            if(x>='a'&&x<='z')
        printf("%d
",-(x-96)+y);
           if(x>='A'&&x<='Z')
       printf("%d
",(x-64)+y);
         
        
            
        }
         
         return 0;
 }*/
//采用函数调用 
 #include<stdio.h>
  int f( char x){
      if(x>='a'&&x<='z')
        return (1);
           if(x>='A'&&x<='Z')
         return (0);}
   int main(){
         int T;
          scanf("%d",&T);
          
   while(T--){
       int y;
             char x;
        getchar();
        
          scanf("%c %d",&x,&y);
        if(f(x) )   printf("%d
",-(x-96)+y);
         if(f(x)==0)      printf("%d
",(x-64)+y);
  } 
         
              return 0; 
                 }