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  • [Leetcode] Climbing Stairs

    You are climbing a stair case. It takes n steps to reach to the top.

    Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

    DP启蒙啊,做完这题终于对DP有个大概的认识了,自底向上检表,建完也就ok了,复杂度是O(n)

    void iter(int acc, int n, vector<int> &table) {
        if (acc < 0) return;
        if (acc == n+1) return;
        int a = acc-1 < 0? 0 : acc-1;
        int b = acc-2 <0? 0 : acc-2;
        table.push_back(table[a] + table[b]);
        iter(acc+1, n, table);
    }
    
    int climbStairs(int n) {
        vector<int> table;
        table.push_back(0);
        table.push_back(1);
        table.push_back(2);
        if (n < 3) return table[n];
        iter(3, n,table);
        return table[n];
    }

    另附纯递归版,当然是TLE的

    int climbstairs_TLE(int n) {
        if (n == 1) return 1;
        if (n == 2) return 2;
        return climbstairs_TLE(n-1) + climbstairs_TLE(n-2);
    }
    TLE
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  • 原文地址:https://www.cnblogs.com/agentgamer/p/4052988.html
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